2 years ago

A bowl contains 28 black, 21 red, 23 blue, and 10 green balls

Mathematics

1 answer:

Licemer1 [7]2 years ago

4 0

Answer:

P (blue) = 23 / 82

Step-by-step explanation:

There are 23 blue out of 82 (28 + 21 + 23 + 10 = 82) balls

or,

23 / 82

So, the probability of a blue ball being chosen is 23/82

(or a 28% chance [rounded])

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