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Ann [662]
2 years ago
11

Choose ALL answer choices listed below which relate to the following scenario: As oil wealth increases in Dubai, Sri Lankan and

Thai citizens migrate to Dubai in search of work. They often work the manual labor jobs such as construction.
0. centrifugal force
0. centripetal force
0. political force
0. economic force
0. social force
0. environmental force
Geography
1 answer:
Wewaii [24]2 years ago
5 0

The answer choices that relate to the scenario are :

  • Centripetal force
  • Economic force

<h3>Effects of workers migration ?</h3>

The migration of the citizens of Sri Lanka and Thailand to Dubai in search of work is, an example of centripetal force because the migrants move towards the center of attraction ( Dubai ) for work.

The migration of Thai and Sri Lanka citizens to Dubai in search of work will lead to an increase in economic force in the city.

Hence we can conclude that The answer choices that relate to the scenario are : Centripetal force and Economic force

Learn more about worker migration : brainly.com/question/7584959

#SPJ1

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a rural kansas watershed that is ungauged has an area of 475 acres and a main channel length of 6870 feet with an average slope
dlinn [17]

Answer:

\mathbf{Q_p  =682 \ \  ft^3/s}

Explanation:

Given that:

Area = 475 acres

The length of the channel (L) = 6870 feet

The average water shield slope (S) = 100 feet/mile

Since; 1 mile = 5280 feet

Burst duration D = 15 min

∴

100 feet/mile = 100/5280

The average water shield slope (S) = 5/264

Using hydrograph method:

The time of concentration t_c = 0.0078L^{0.77} S^{-0.385}

where;

L = 6870

S = 5/264

t_c = 0.0078(6870)^{0.77} (\dfrac{5}{264})^{-0.385}

t_c =32.34 min

Since 60 min = 1 hour

32.34 min will be (32.34*1)/60

= 0.539 hour

Lag time T_l = 0.67\times t_c

T_l = 0.67\times 32.34

T_l = 21.6678\ min

The time to peak i.e

T_p = \dfrac{D}{2}+ T_L \\ \\  T_p = \dfrac{15}{2}+ 21.6678 \\ \\  T_p = 29.168 \ min

T_r = \dfrac{T_p}{5.5} \\ \\  T_r = \dfrac{29.1678}{5.5} \\ \\ T_r = 5.30 \ min

Since D = 15 min is not equal to T_r, then we hydrograph apart from T_r duration lag time.

Then;

T_p \ ' = T_p + \dfrac{D-t_r}{4} \\ \\ T_p \ ' = 29.168 + \dfrac{15-5.30}{4} \\ \\ T_p \ ' = 31.593

Now, we need to determine the peak discharge Q_p by using the formula:

Q_p  = \dfrac{484 \times A}{T_p \ '}

where

484 = peak factor

Recall that A = 475 acres, to miles, we have:

A = 0.7422 mile²

T_p \ ' = 31.593/60

∴

Q_p  = \dfrac{484 \times 0.7422}{\dfrac{31.593}{60}}

\mathbf{Q_p  =682 \ \  ft^3/s}

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