Which equation is g(f)
1 answer:
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Answer: (-2, 0) and (0, -2)
Step-by-step explanation:
This system is:
y + x = -2
y = (x + 1)^2 - 3
To solve this we first need to isolate one of the variables in one fo the equations, in the second equation we have already isolated the variable y, so we can just replace it in the first equation:
(x + 1)^2 - 3 + x = -2
Now we can solve this for x.
x^2 + 2*x + 1 - 3 = -2
x^2 + 2*x + 1 -3 + 2 = 0
x^2 + 2*x + 0 = 0
The solutions of this equation are given by the Bhaskara's formula, then the solutions are:
The two solutions are:
x = (-2 - 2)/2 = -2
In this case, we replace this value of x in the first equation and get:
y - 2 = -2
y = -2 + 2 = 4
This solution is x = -2, y = 0, or (-2, 0)
The other solution for x is:
x = (-2 + 2)/2 = 0
If we replace this in the first equation we get:
y + 0 = -2
y = -2
This solution is x = 0, y = -2, or (0, -2)
Check the picture below.
if we know the endpoints of the circle, then its center must be the midpoint of those two endpoints.
Answer: x= 8
Step-by-step explanation:
According to the converse of basic proportionality theorem,
If in ΔABC , DE is a line drawn from AB to AC such that
then, DE is parallel to the third side BC.
Applying converse of basic proportionality theorem, to get NO parallel to KJ, we must have
Hence, the value of x should be 8, so that Line segment N O is parallel to line segment K J.
