Does someone mind helping me with this question? Thank you!

Mathematics

1 answer:

Phantasy [73]2 years ago

3 0

Step-by-step explanation:

8(3x+1)

=24x+1

I'm not sure

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Hello there! How to find the probability? See picture! Thank you and please show your work!

german

Answer:

0.8914

Step-by-step explanation:

You want to find the z-values associated with the x-values:

z = (x -μ)/σ

z1 = (57 -90)/12 = -2.75

z2 = (105 -90)/12 = 1.25

Look up these values in a probability table and find the difference of the table values.

p(z < z1) ≈ 0.00298 . . . . from a table or calculator

p(z < z2) ≈ 0.89435 . . . . from a table or calculator

p(57 < x < 105) ≈ 0.89435 -0.00298 = 0.89137 ≈ 0.8914

8 0

4 years ago

Factor the quadratic expression completely.<br>-8x^2 -15x + 2 =

Westkost [7]

Answer:

Step 1: −8x2−15x+2

Step 2: (−8x+1)(x+2)

Step 3: Say thank you

7 0

3 years ago

A box contains four bowling balls numbered 2, 4, 6, and 10 according to their weight. Two are drawn randomly without replacement

Lilit [14]

Answer:

E(M) = 23/3

Var(M) = 53/9.

Step-by-step explanation:

There are three possible values for M: 4, 6, and 10.

$\begin{array}{|l|l|}\cline{1-2}\\[-1em]\text{Larger Number} & \text{Smaller Number}\\ \cline{1-2}\\[-1em]4 & 2 \\\cline{1-2}\\[-1em]6 & 2, ~4\\\cline{1-2}\\[-1em] 10 & 2, ~4, ~6\\\cline{1-2} \end{array}$ .

That's six unique combinations in total. If the balls are drawn randomly, the probability for getting each combination shall be equal. That is:

$\begin{array}{|c|c|}\cline{1-2}\\[-1em]m & P(\text{M} = m)\\\cline{1-2}\\[-1em] 2 & 0\\\cline{1-2}\\[-1em] 4 & 1/6 \\\cline{1-2}\\[-1em] 6 & 2/6\\\cline{1-2}\\[-1em] 10 & 3/6\\\cline{1-2}\end{array}$ .

Consider the formula for the expected value of a discrete random variable:

$\begin{aligned} E({\rm M})& = \sum{[m \cdot P(\mathrm{M} = m)]}\\ &= 4 \times \frac{1}{6} + 6\times \frac{2}{6} + 10 \times \frac{3}{6}\\ &= \frac{23}{3}\end{aligned}$ .

Formula for the variance of a discrete random variable (note that this formula can take many other forms):

$\begin{aligned}Var(\mathrm{M}) &= \sum{[m^{2}\cdot P(\mathrm{M}= m)]} - \mu^{2}\\&= 4^{2}\times \frac{1}{6} + 6^{2} \times \frac{2}{6} + 10^{2} \times \frac{3}{6} - \left(\frac{23}{3}\right)^{2}\\&= \frac{53}{9}\end{aligned}$ .