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2 years ago

PLEASE HELP I NEED THE ANSWER ASAP !! TYSM !

Mathematics

1 answer:

Tom [10]2 years ago

6 0

a) Radicand is 1/4

b) x= 4.5 or -2.5

<h3>What is quadratic equation?</h3>

A quadratic equation is a second-order polynomial equation in a single variable x ax²+bx+c=0. with a ≠ 0 .

Given equation is:

16x²-8x+1=0

Now,

(4x)²-2*4x*1 + (1)²=0

Using

(a+b)²= a² + 2ab + b²

So,

(4x)²-2*4x*1 + (1)² = (4x+1)²

x=1/4

b) 4x² - 8x - 45 = 0

Using discriminant method

D = √[(-8)² - 4(4)(-45)]

= √784

= 28

Now, x = (1/8)[8 +/- 28]

= (1/8)(36) = 4.5

or, x = (1/8)(-20)

= -2.5

Learn more about this concept here:

brainly.com/question/4480807

#SPJ1

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3 years ago

URGENT !!!!!!! Please answer correctly !!!!!!!!!!!! Will be marking Brianliest !!

brilliants [131]

Answer:

A=79.2 $in^{2}$

Step-by-step explanation:

A=a+b/2*h

A=5.4+14.4/2*8

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3 years ago

Based on the pull of gravity which model shows how long it will take the ball to hit the ground?

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3 years ago

A and B are independent events. P(A) =0.30 P(B) = 0.60<br><br>What is P(A|B)?

Tatiana [17]

Answer:

P(A|B) = 0.30

Step-by-step explanation:

P(A) = 0.30

P(B) = 0.60

To Find:

P(A|B) = ?

P(A|B) means probability of occurring of event A when event B has occurred.

P(A|B) = P(A∩B)/P(B)

We know that for independent events;

P(A∩B) = P(A).P(B)

So, we have:

P(A|B) = P(A).P(B)/P(B)

P(A|B) = P(A)

So, probability of occurrence of an independent event does not depend on the probability of a different event.

7 0

4 years ago

Read 2 more answers

The Acculturation Rating Scale for Mexican Americans (ARSMA) is a psychological test that measures the degree to which Mexican A

aleksandr82 [10.1K]

Answer:

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The distribution of ARSMA scores in a population used to develop the test is approximately Normal with mean 3.0 and standard deviation 0.8.

This means that $\mu = 3, \sigma = 0.8$

What proportion of the population used to develop the test has scores below 1.7?

This is the pvalue of Z when X = 1.7. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1.7 - 3}{0.8}$

$Z = -1.63$

$Z = -1.63$ has a pvalue of 0.063

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

Between 1.7 and 2.1?

This is the pvalue of Z when X = 2.1 subtracted by the pvalue of Z when X = 1.7.

X = 2.1

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2.1 - 3}{0.8}$

$Z = -1.13$

$Z = -1.13$ has a pvalue of 0.1292

X = 1.7

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1.7 - 3}{0.8}$

$Z = -1.63$

$Z = -1.63$ has a pvalue of 0.063

0.1292 - 0.063 = 0.0662

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

3 0

3 years ago