A useful dilution relationship is (M1V1)=(M2V2) where M is molarity and V is volume in liters.
(6.00M x V1) = (2.00M x .500L) (I assume you mean 2.0M)
V1= (2.00M x .500L)/6.00M
V1= 0.167L
At room temperature:
a. Gold is a solid, as in the gold jewelry that most people have.
b. Gasoline is a liquid, as it is pumped in cars to use as fuel.
c. Oxygen is a gas, as we breathe it in from the atmosphere.
d. Neon is a gas, it is one of the noble gases in the periodic table.
e. Olive oil is a liquid, as it is used in cooking.
f. Sulfur is a solid, and it can be found naturally in mining.
g. Mercury is a liquid which is often seen in thermometers.
Answer: The concentration of the KOH solution is 1.01 M
Explanation:
According to neutralization law:
where,
= basicity of = 1
= acidity of KOH = 1
= concentration of HCl = 3.00 M
= concentration of KOH = ?
= volume of HCl = 35.3 ml
= volume of KOH = 105.0 ml
Putting the values we get:
Thus the concentration of the KOH solution is 1.01 M