The dog house consists of two geometric objects, triangular prism and rectangular prism.
First, find the surface area of triangular prism
The triangular prism consists of
base of triangle (b) = 3 ft
height of triangle (h) = 2.5 ft
height of prism or length of rectangle (l) = 4 ft
side of triangle or width of rectangle (w) = 2.5 ft
Now, calculate the area
area of tp = area of two triangle + area of 2 rectangle
area of tp = (2 × 1/2 × b × h) + (2 × l × w)
area of tp = (2 × 1/2 × 3 × 2) + (2 × 4 × 2.5)
area of tp = 6 + 20
area of tp = 26 ft²
Second, find the surface area of rectangular prism
The rectangular prisms consists of
length (l) = 3 ft
width (w) = 4 ft
height (h) = 2 ft
Now, calculate the area
area of rp = area of back and front rectangle + area of left and right rectangle
area of rp = (2 × l × h) + (2 × w × h)
area of rp = (2 × 3 × 2) + (2 × 4 × 2)
area of rp = 12 + 16
area of rp = 28 ft²
Third, add both of the area
area = area of tp + area of rp
area = 26 + 28
area = 54 ft²
The area of the dog house is 54 ft²
Answer:
17%
Step-by-step explanation:
If 30% of the school is girls and 10% wear glasses, that means that at least 3% of the school wears glasses. (10 percent of 30%) If 70% of the school is boys and 20% of boys wear glasses, at least 14% of the school wears glasses. (20% of 70%) If you add both of those numbers together it adds up to 17%.
Assuming you are asking how many weeks, than the answer would be 17-32, because at 16 weeks the growth would be 4 cm, totaling at 11, but you need more than 11cm, and at 32 weeks it's at 15 cm.
Answer:
So, the interquartile range is IQR=22.5.
Step-by-step explanation:
Let us write the numbers in ascending order:
34, 37, 38, 40, 44, | 46, 50, 51, 55, 56, |
57, 61, 62, 65, 65, | 68, 68, 72, 73, 76.
We calculate quartile 1:

We calculate quartile 2:

We calculate quartile 3:

We calculate the interquartile range:

Answer:
x = 2.67
Move variables to the right and constants to the left, Then divide and you get the answer.
Step-by-step explanation:
-1.3+4.6x=0.3+4x (given)
-1.3x + 0.6x =0.3 (subtraction property of equality)
0.6x = 1.6 (addition property of equality)
x = 2.66666666667 (division property of equality)
2.66666666667 = 2.67 (rounding to the nearest tenth)