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2 years ago

Ivan bought a $1000 bond with a 4.5% coupon that matures in 30 years. What

Mathematics

1 answer:

Flura [38]2 years ago

5 0

Ivan's annual earnings for this bond is $45.00

A bond is a pledge, made by a borrower to pay a loan taken back to the lender with an interest.

Ivan's annual interest earning would be :

= $1,000 x 4.5 %

= $45 per year

Hence, Ivan's annual earnings for this bond is $45.00

Learn more about bonds here : brainly.com/question/1392006

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The sum of 3 times a and 4 is the same as five

kupik [55]

Answer:

3a +4 = 5

Step-by-step explanation:

that is the answer i don't know how to explain it.

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3 years ago

The value of x that satisfies the equation 4/3=x+10/15

kenny6666 [7]

For this case we must find the value of "x" that meets the following equation:

$\frac {4} {3} = x + \frac {10} {15}$

We subtract $\frac {10} {15}$ on both sides of the equation:

$\frac {4} {3} - \frac {10} {15} = x\\\frac {15 * 4-3 * 10} {3 * 15} = x\\\frac {60-30} {45} = x\\- \frac {30} {45} = x$

We simplify:

$x =\frac {6} {9}=\frac{2}{3}$

Finally, $x =\frac {2} {3}$

Answer:

$x =\frac {2} {3}$

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3 years ago

Please Help This is for math Homework

Molodets [167]

Answer:

id say 4 google's calculator is a good math helper as well

Step-by-step explanation:

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3 years ago

A cereal company is putting 1 of 3 prizes in each box of cereal. The prizes are evenly distributed so the

Fittoniya [83]

Answer:

0.625

Explanation:

The image below was not posted for the but is needed to anser the question.

Further Explanation:

Mohamed carried out 24 trials of a simulation

Therefore, Total frequencies = 24

To get number of frequency greater than 3 we have to use the result in the result in the graph to obtain the estimate. Look at the graph below, when you count the dots that are on number of boxes purchased greater than 3, you will get 15.

Therefore, Number of frequency greater than 3 = 15

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3 0

3 years ago

An English teacher needs to pick 9 books to put on his reading list for the next school year, and he needs to plan the order in

Nikitich [7]

Answer: $4.37\times10^3$

Step-by-step explanation:

Given : Number of choices for novels = 4

Number of choices for plays = 6

Number of choices for poetry books = 5

Number of choices for nonfiction books = 5

Total books =4+6+5+5=20

If he wants to include all 4 novels, then the number of books left to select = 9-4=5

Remaining choices for books = 20-4=16

Number of combinations of n things taking r at a time : $\dfrac{n!}{r!(n-r)!}$

Then, the number of different reading schedules are possible :_

$^4C_4\times^{16}C_5\\\\=\dfrac{4!}{4!(4-4)!}\times\dfrac{16!}{5!(16-5)!}\\\\=(1)\times\dfrac{16\times15\times14\times13\times12\times11!}{120\times11!}\\\\=4368=4.368\times10^3\approx4.37\times10^3$

Hence, the required answer is $4.37\times10^3$ .

8 0

3 years ago