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gizmo_the_mogwai [7]
2 years ago
6

Suppose we want to choose 7 objects, without replacement, from 10 distinct objects.

Mathematics
1 answer:
Citrus2011 [14]2 years ago
7 0

Answer:

= 604800

Step-by-step explanation:

10 permute 7

the order matters

10 x 9 x8 x7 x6 x5 x4

hope this helps

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Solve the following system of linear equations. 3x + 2y = 10 2x + 3y = 15/2 No solution y = (-3/2)x + 5 x = 3, y = -1/2 x = 3, y
frutty [35]
3x + 2y = 10 .....multiply by -2
2x + 3y = 15/2...multiply by 3
------------------
-6x - 4y = -20 (result of multiplying by -2)
6x + 9y = 22.5 (result of multiplying by 3)
-----------------add
5y = 2.5
y = 2.5/5
y = 1/2

3x + 2y = 10
3x + 2(1/2) = 10
3x + 1 = 10
3x = 10 - 1
3x = 9
x = 9/3
x = 3

solution is (3,-1/2)
5 0
3 years ago
Hey can someone plz help me with this??? *cute eyes*
Leto [7]

Answer:

A. 5

B. -5, 5

C. 5, 5

Step-by-step explanation:

A. |-6+(-1)| = 5

B. -6-(-1)=-6+1=-5

-1-(-6)=-1+6=5

C. |-6-(-1)|=|-6+1|=5

|-1-(-6)|=|-1+6|=5

5 0
3 years ago
Select all the correct answers. Which two inequalities can be used to find the solution to this absolute value inequality? 3|x +
ziro4ka [17]

The absolute value inequality can be decomposed into two simpler ones.

x < 0

x > -8

<h3></h3><h3>Which two inequalities can be used?</h3>

Here we start with the inequality:

3|x + 4| - 5 < 7

First we need to isolate the absolute value part:

3|x + 4| < 7 + 5

|x + 4| < (7 + 5)/3

|x + 4| < 12/3

|x + 4| < 4

The absolute value inequality can now be decomposed into two simpler ones:

x + 4 < 4

x + 4 > - 4

Solving both of these we get:

x < 4 - 4

x > -4 - 4

x < 0

x > -8

These are the two inequalities.

Learn more about inequalities:

brainly.com/question/24372553

#SPJ1

6 0
1 year ago
What is the solution to the system? 1. x-y + 2 z = -7<br> 2. y + z =1<br> 3. x-2 y - 3 z = 0
kvv77 [185]

You'd find this problem easier to understand and do if you'd please list the defining equations vertically and line up variables:

1. x - 1y + 2 z = -7

2. y + 1z = 1

3. x - 2 y - 3 z = 0 Now eliminate the line numbers:

x - 1y + 2 z = -7

1y + 1 z = 1

x - 2 y - 3 z = 0

Let's use the elimination method to eliminate variable z: Seeing that z = 1 - y, we transform the first equation into 1x - 1y + 2(1-y) = -7

and the third into x - 2y - 3(1-y) = 0.

Simplifying 1x - 1y + 2(1-y) = -7

and x - 2y - 3(1-y) = 0,

we get

1x - 2y - 3 + 3y) = 0 and 1x - 1y + 2 - 2y = -7

which in turn simplify to

1x + y = 3 and 1x - 3y = -9

Having eliminated the variable z, we now focus on eliminating x. Mult. the 1st equation by -1, obtaining -1x - 1y = -3. Add this result to 1x - 3y = -9:

0 - 4y = -12, which tells us that y = 3. Subbing 3 for y in 1x + 1y = 3 tells us that x = 0.

All we have left to determine is the vaue of z.

Borrowing Equation 3, from above, we get x - 2 y - 3 z = 0, and into this equation we substitute x = 0 and y = 3: 0 -2(3) - 3z = 0.

Thus, -3z = 6, and z = -2.

The solution set is (0, 3, -2). You should check this by substitution.

3 0
3 years ago
Calculate the perimeter of a square with vertices on a circle of diameter 4 cm
posledela

Answer:

I dont like sqaures.

Step-by-step explanation: Their pointy.

3 0
3 years ago
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