All categories

2 years ago

A jewelry store has 88 rings to display they arrange the rings in a even rose how many rings are in each row

Mathematics

1 answer:

Ipatiy [6.2K]2 years ago

8 0

Answer:

2,4,8,11,22, or 44

Step-by-step explanation:

To figure out how many rings would be in each full row with no leftovers, we need to find all the factors of 88 (outside of 1 and 8) which are 2,4,8,11,22, and 44. Since the question does not give any more information on how big the rows need to be, I can't narrow this down any further, however if I had to choose I would say rows of 8 by 11 would be the best.

Hope this helps! :)

You might be interested in

What is the median of these numbers: 1, 2, 3, 3, 4, 6, 8, 9, 10?

monitta

Answer: 4

Step-by-step explanation: The answer is 4 because, to find the median you must put the numbers in order and find the one in the middle . Which makes the answer 4 :)

7 0

3 years ago

Read 2 more answers

In Mark's collection of antique bottles, 1 over 2 of of the bottles are dark green. Write three equivalent fractions for 1 over

dalvyx [7]

Answer:

2/4, 3/6, and 4/8

Step-by-step explanation:

Equivalent fractions are made by multiplying the numerator and denominator by the same factor.

For 1/2, you can multiply the top and bottom by 2, 3, or 4 to get 2/4, 3/6, and 4/8 respectively.

3 0

3 years ago

I need help PLEASE!!!!!!!!

PIT_PIT [208]

Answer:

Step-by-step explanation:

<h2>the letter in the problem is the missing number</h2>

3 0

3 years ago

If angle ABE = 5x+1 and angle CBD = 3x+19

kolbaska11 [484]

the answer to this is
Angle ABE= 56
Angle CBD= 56
Angle ABC= 124

3 0

3 years ago

Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n

Nady [450]

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

The maclaurin series for f(x) is defined by the following formula:

$f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}$ --------------(1)

Where $f^{i}$ is the i - th derivative of the function

If f(x) = $e^{-6x}$ , then the formula of the i - th derivative of the function is:

$f^{i} =(-6)^{i} .e^{-6x}$ ----------------------(2)

Then,

$f^{i}(0) = (-6)^{i}$

Lastly, the equation of the trascendental function by Maclaurin series is: $f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i} }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ ---------------(3)

Hence,

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

Find out more information about maclaurin series here

brainly.com/question/24179531

#SPJ4

4 0

2 years ago