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Ugo [173]
2 years ago
14

1. 5 M 20 CM of cloth is needed to stitch a shirt how much clothes will be needed to stitch 449 shirts

Mathematics
1 answer:
Ratling [72]2 years ago
6 0

#1

Length in cm

  • 500+20=520cm
  • Shirts=449

Total length

  • 449(520)
  • 233480cm
  • 2334m 80cm

#2

Total notes

  • 425-412+1=14

Total money

  • 100(14)
  • 1400

|

Total suits per month=120

per year

  • 120(12)
  • 1440suits

#4

Total 5mins

  • 50/5=10

total distance

  • 348(10
  • 3480m
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In the game Kazoo, teams lose one point each time they skip a turn. They earn one point each time their team guesses correctly.
lbvjy [14]

Answer:

-8 + 6 = - 2

So the answer is - 2

5 0
3 years ago
sally has 20 coins in her piggy bannk, all dimes and quarters. the total amount of money is $3.05. how many of each coin does sh
VMariaS [17]
D=dimes
q=quarters

d + q = 20
.10d + .25q = 3.05

d=-q + 20

.10(-q + 20) +.25q = 3.05
-.10q + 2 + .25 = 3.05
.15q + 2 = 3.05
.15q + 2 - 2 = 3.05 - 2
.15q = 1.05
.15q/.15 = 1.05/.15
q = 7

d + 7 = 20
d + 7 - 7 = 20 - 7
d = 13

Sally has 7 quarters and 13 dimes.
Hope this helps!
5 0
3 years ago
The sum of four consecutive integers is 390. Find the integers (Please show your work)
AysviL [449]

Step-by-step explanation:

The sum of three consecutive even integers is 390. What are the integers?

 

   In order to ensure the numbers are even I generally call the first

   integer 2n  because 2 multiplied by any number will always be even.

   Our consecutive even integers are:  2n, 2n+2, 2n+4

 

   2n + 2n+2 + 2n+4 = 390

   6n + 6 = 390

   6n = 384

   n = 64

 

  Our 1st integer is 2n = 2(64) = 128

  Our integers are 128, 130, 132

 

Check:  128+130+132 = 390 which is correct.

 

2) The sum of three consecutive odd integers is 99. What are the integers?

 

    Same logic applies:  An odd integer will always result from 2n+1

    So we will call our 3 consecutive odd integers   2n+1, 2n+3, 2n+5

 

   2n+1 + 2n+3 + 2n+5 = 99

   6n+9 = 99

   6n = 90

   n = 15

   Our first odd integer is 2n+1 = 2(15) + 1 = 31

   Our 3 consecutive odd integers are 31, 33, 35

 

Check:  31 +33+45 = 99  Yes

 

3)Which equation defines three consecutive odd integers that add up to 81?

A) n(n+1)(n+2)=81

B) n(n+2)(n+4)=81

C) n+(n+1)+(n+3)=81

D) n+(n+1)+(n+2)=81

E) n+(n+2)+(n+4)=81

 

We can immediately discard answers A, B because they are multiplying

instead of adding.

That leaves C, D, E

 

This question does not follow the logic I utilized in question 1 and 2. 

Assuming the first number is indeed odd and is called n

The next odd number is n+2 followed by n+4

Thus we must have:  n + (n+2) + (n+4) = 81

The answer is E

 

By the way:  The numbers are 25, 27, 29

5 0
3 years ago
Read 2 more answers
Select the correct answer. Consider these three numbers written in scientific notation: 6. 5 × 103, 5. 5 × 105, and 1. 1 × 103.
Karo-lina-s [1.5K]

Scientific notation uses expression which gives easy access of order. The greatest number is 5.5 \times 10^5 .It is greater by smallest number by 500  times.

<h3>How to convert a number to scientific notation?</h3>

It is usually of the form a.bc.. \times 10^kexponent of 10 starts)

(we have 1 ≤ |a| < 10 ) (where |a| is magnitude of a without sign)

This notation is used to get some idea of how large or small a number is in terms of power of 10.

<h3>What are some basic properties of exponentiation?</h3>

If we have a^bbase and 'b' is called power or exponent and we call it "a is raised to the power b" (this statement might change from text to text slightly).

Exponentiation(the process of raising some number to some power) have some basic rules as:

a^{-b} = \dfrac{1}{a^b}\\\\a^0 = 1 (a \neq 0)\\\\a^1 = a\\\\(a^b)^c = a^{b \times c}\\ a^b \times a^c = a^{b+c}

The given numbers are:

  • First number = 6.5 \times 10^3 = 6500
  • Second number = 5.5 \times 10^5 = 550000
  • Third number = 1.1 \times 10^3 = 1100

The smallest number is 1,100 and greatest is 550,000

Getting the division to get to know how many times the greatest number is larger than the smallest number, we get:

\dfrac{5.5 \times  10^5}{1.1 \times 10^3} = \dfrac{5.5 \times 10^{5-3}}{1.1} = \dfrac{5.5}{1.1} \times 10^2 = 5 \times 10^2 = 500

Thus, it is found that greatest number is 5.5 \times 10^5 . It is greater by smallest number by 500  times.

Learn more about scientific notation here:
brainly.com/question/3112062

6 0
3 years ago
Use subtraction<br> 8 x 25 x 23
andreyandreev [35.5K]

You cant subtract from a multiplication expression.

If there is a way.. im not sure.

3 0
4 years ago
Read 2 more answers
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