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2 years ago

a rule that assigns each value of the independent variable to exactly one value of the dependent variable?

Mathematics

1 answer:

e-lub [12.9K]2 years ago

3 0

Answer:

Answer:- Function

please mark me as brainliest

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The savings account offering which of these APRs and compounding periods offers the best APY?

ANTONII [103]

A)

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1196\%\to \frac{3.1196}{100}\to &0.031196\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left. \qquad \qquad\right. \left(1+\frac{0.031196}{2}\right)^{2}-1$

b)

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1184\%\to \frac{3.1184}{100}\to &0.031184\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four times}
\end{array}\to &4
\end{cases}
\\\\\\
\left. \qquad \qquad\right. \left(1+\frac{0.031184}{4}\right)^{4}-1$

c)

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1095\%\to \frac{3.1095}{100}\to &0.031095\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, assuming 365 days}
\end{array}\to &365
\end{cases}
\\\\\\
\left. \qquad \qquad\right. \left(1+\frac{0.031095}{365}\right)^{365}-1$

d)

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1172\%\to \frac{3.1172}{100}\to &0.031172\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve times}
\end{array}\to &12
\end{cases}
\\\\\\
\left. \qquad \qquad\right. \left(1+\frac{0.031172}{12}\right)^{12}-1$

8 0

4 years ago

Read 2 more answers

Solve for C

valina [46]

Answer:

c=d/a-b

Step-by-step explanation:

a(c+b)=d

c+b=d/a

c=d/a-b

5 0

3 years ago

Find the first three terms of the sequence below n² – n + 4

sergejj [24]

Answer:

First three terms of given sequence are

9, 13, 17

Step-by-step explanation:

3 0

3 years ago

How do you factor quadratic expressions with coefficient and without c?

Volgvan

Answer:

Completing the square. I mean, you can, for some values of a and b, but it's not going to help much if it is messy. Nope!

Factoring. Yes. It's really easy since there is an obvious common factor.

Square root theorem. No idea what this is. And I don't know how it would help.

Quadratic equation. This works, but is a little long for what you have to do.\

3 0

3 years ago

Answer both for brainiest, 40 points, and thanks with 5 stars

tankabanditka [31]

Answer:

17) #1 = 5

#2 = 49

18) Median= 50.5

Range = 88

Step-by-step explanation:

17) #1 - There are 5 3’s on the leaf side.

#2 - The number that is shown the most times is 49

18) There are 30 numbers in the stem and leaf plot, so the median falls between numbers 15 and 16. In this plot, those numbers are 50 and 51. So the median is 50.5.

The data ranges from 10 to 98. 98-10=88

7 0

4 years ago