Length (L): 4w + 1
width (w): w
Perimeter (P) = 2L + 2w
62 = 2(4w + 1) + 2(w)
62 = 8w + 2 + 2w
62 = 10w + 2
60 = 10w
6 = w
Length: L = 4w + 1 → 4(6) + 1 → 24 + 1 → 25
Answer: 6 meters x 25 meters
Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has

and

.
Since O lies in second quadrant

and

.
Answer:
.
The answer is
C) -7
Multiply -5 by 2
Divide 8 by 4 :
3-10+2-2
Subtract 10 from 3 :
-7+2-2
Add -7 and 2 :
-5 - 2
Subtract 2 from -5:
-7