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andrezito [222]
2 years ago
15

2x+y=8 simplify all fractions

Mathematics
1 answer:
Mrac [35]2 years ago
7 0

The simplified form of the given equation ( 2x + y = 8 ) is x = 4 - y/2.

<h3>Simplify all fractions?</h3>

Give the equation;

  • 2x + y = 8
  • Simplify

2x + y = 8

Subtract -y from both sides

2x + y - y = 8 - y

2x = 8 - y

Divide both sides by 2

2x/2 = ( 8 - y )/2

x = 8/2 - y/2

x = 4 - y/2

Therefore, the simplified form of the given equation ( 2x + y = 8 ) is x = 4 - y/2.

Learn more about equations here: brainly.com/question/14686792

#SPJ1

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Colt1911 [192]

Answer:

Answer: 1/81

First you simplify it to 3^-4

Then express it with a positive exponent

which goes to 1/3^4

Then evaluate it to 1/81

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Please Help extra points
Molodets [167]
<h2>A. $123.51</h2><h2 />

1^{st}: $24.48 per year + price * 0.85

2^{nd}: $36.83 per year + price * 0.75

Substitute each value into both equations as price.

A:

129.4635

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B:

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C:

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A is the lowest value where the second value is lower than the first.

3 0
4 years ago
Solve the following quadratic by factoring.
Lina20 [59]

Answer:

4, -1

Step-by-step explanation:

We can reverse the FOIL (First, outside, inside, last) method to break down the equation. The question is asking to solve by factoring so you want to find the right combination of numbers this equation can be broken down into:

x^2 - 3x - 4 = 0

Because we want x squared, x needs to be multiplied by itself, so we can put x in the first slot for each.

(x + or - ?) ( x + or - ?) = 0

Then we need to find numbers that could be added to get -3 and multiplied to get -4. The only set of numbers that works for this is -4 and 1. Note that the sign you put in front of each number has an impact on your answers. With this we get:

(x - 4) (x + 1) = 0

To test that this is equal to the original equation, simply multiply it out using FOIL.

x * x = x^2

x * 1 = x

x * -4 = -4x

-4 * 1 = -4

Putting each component into an equation:

x^2 + x - 4x - 4 = 0

Simplifying:

x^2 - 3x - 4 = 0

Once we are sure it is still the same equation, we find the solutions. We know 0 multiplied by anything equals 0, so to get 0 as the answer, one of the sets in the parentheses must equal 0. (It doesn't matter what the other one is as long is one equals 0)

Therefore, we have 2 solutions, 4, and -1 because if x is 4, 4-4 is 0 which solves the equation, and if x is -1, then -1 + 1 is 0 which also solves the equation.

You can also check your answers by plugging them back into the original equation.

5 0
3 years ago
A committee of 5 people is to be chosen from a group of 8 women and 10 men. How many diffferent committees are possible? How man
Jet001 [13]
A) 5 to be chosen among a Total : 10 Men + 8 Women

¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five

b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56

So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees 

c) 3 Women and 2 Men:

⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M

d) More women than men, it means:
  3 W + 2 M OR (we have found it in c) = 2,520)
  4 W + 1 M OR   ⁸C₄ x ¹⁰C₁   →→→→ =    700
  5 W + 0 M OR   ⁸C₅ x ¹⁰C₀   →→→→  =     56

Total where W>M = 3,276 groups of 5 where women are at least 3


3 0
3 years ago
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