4x+2x+6 (which is ab plus bc)
6x+6 (the length of ac)
sin(x+y)=sin(x)cos(y)-cos(x)sin(y)
also, remember pythagorean rule, 
given that sin(Θ)=4/5 and cos(x)=-5/13
find sin(x) and cos(Θ)
sin(x)
cos(x)=-5/13
using pythagorean identity
(sin(x))^2+(-5/13)^2=1
sin(x)=+/- 12/13
in the 2nd quadrant, sin is positve so sin(x)=12/13
cos(Θ)
sin(Θ)=4/5
using pythagrean identity
(4/5)^2+(cos(Θ))^2=1
cos(Θ)=+/-3/5
in 1st quadrant, cos is positive
cos(Θ)=3/5
so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)
sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)
sin(Θ+x)=16/65
answer is 1st option
You know that a perfect square trinomial is given by square of first term, twice the product of first and last terms and square of second term
So we have x^2 that is square of x, 2x that is twice the product of x*1, the second term shoulf be 1, that is square of 1
So your answer would be 1
If you try (x+1)^2 = x^2+2x+1
Answer:
0
Step-by-step explanation:
Y2-y1/x2-x1
5-5/9-10 =0/-1. Slope is 0
Stuck on the same thing, tried reviewing and reviewing but now I’ll just try finding the answer key