Answer:
C)
Explanation:
One principle that can improve the efficiency of I/O would be to move processing primitives into hardware. Primitives are a semantic value representing something else such as words or numbers within the programming language. By moving them into hardware they system is able to read them at a much faster speed making the I/O more efficient.
Answer:
#include <iostream>
using namespace std;
int main()
{
int side1=0;
int side2=0;;
int side3=0;
cout <<"Enter side one measurement";
cin >> side1;
cout <<"Enter side two measurement";
cin >> side2;
cout <<"Enter side three measurement";
cin >> side3;
if(side1+side2>side3||side1+side3>side2||side2+side3>side1){
if (side1==side2 && side2==side3)
{
cout <<"equilateral triangle"<<endl;
}
else if(side1==side2||side2==side3||side1==side3){
cout <<"Isosceles triangle"<<endl;
}
else{
cout <<"scalene triangle"<<endl;
}
}else{
cout<<"No triangle";
}
return 0;
}
Explanation:
The code is written in c++. It takes measurements of each side from users as input and check the types of triangle based on the following formula.
1. Equilateral Triangle
If all sides of a triangle are equal than it's an equilateral triangle.
2. Isosceles Triangle
If any two sides of a triangle are equal than it's an Isosceles triangle.
3. Scalene Triangle
If all the sides of a triangle are of different length than it's an Scalene triangle.
In a triangle the sum of two sides is greater than third side otherwise it's not a triangle.
An optimization problem is one in which you want to find, not just a solution, but the best solution •<span>A <span>“greedy algorithm” sometimes works </span></span><span>well for optimization problems </span>•<span>But only a few optimization problems can </span><span> be solved by the <span>greedy method</span></span>
Answer:
See picture.
Explanation:
The picture shows all the 8 coordinates.
Answer:
C
Explanation:
The know-nothing party was a strong anti catholic party and anti-immigration party, so that rules out the first option. Also we can rule out the second and last options because they have less to do with the party. The answer would be C.