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2 years ago

Select the correct answer. Simplify. 198 49√2 OB. 7√2 OC. 2√7 OD. 14√7

Mathematics

1 answer:

Nitella [24]2 years ago

7 0

Answer: The correct answer is B.

Step-by-step explanation: To simplify a square root, you take the factors of the value in the square root and see the greatest factor that is a square. In this case, 49 is the greatest square factor of 98. You take the square root of 49, which is 7. 7 goes outside the radicand. Leave 2 inside the radical because 49 x 2 = 98. Hence, the correct answer is B.

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The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V. Write the direct variation e

kow [346]

Answer:

$D=kV^2$

Step-by-step explanation:

In this problem, it is given that,

The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V.

We need to write the direct variation equation for the scenario above. It can be given by :

$D\propto V^2$

To remove the constant of proportionality, we put k.

$D=kV^2$

k is any constant

Hence, this is the required solution.

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2 years ago

A gallon of water weighs 8.354 pounds.simon uses 11.81 gallons of water taking a shower.about how many pounds of water did simon

Helga [31]

98.66074, you just multiply the two values

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3 years ago

At the Science Museum, there is an exhibition with 150 displays about energy.

tatuchka [14]

<span>1/5

This is a matter of elimination. So let's figure out how many of each display there is. 30% of 150 = 0.30 * 150 = 45 displays about electricity. 2/5 * 150 = 0.40 * 150 = 60 displays about renewable energy 1/10 * 150 = 150/10 = 15 displays about gas. The rest of the displays are about nuclear power. So 150 - 45 - 60 - 15 = 30 displays about nuclear power. Since we want a fraction, we get 30/150 But 30/150 isn't in it's simplest form. The largest number that will evenly divide both 30 and 150 is 30. So divide both the numerator and denominator by 30 (30/30)/(150/30) = 1/5 So 1/5 of the displays are about nuclear power.</span>

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3 years ago

A right triangle has three sides with length 148, 140, and 48. What is the length of the hypotenuse?

Oksanka [162]

145 i think im only three

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3 years ago

(10 points)Assume IQs of adults in a certain country are normally distributed with mean 100 and SD 15. Suppose a president, vice

vesna_86 [32]

Answer:

0.0139 = 1.39% probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Step-by-step explanation:

To solve this question, we need to use the binomial and the normal probability distributions.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability the president will have an IQ of at least 107.5

IQs of adults in a certain country are normally distributed with mean 100 and SD 15, which means that $\mu = 100, \sigma = 15$

This probability is 1 subtracted by the p-value of Z when X = 107.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{107.5 - 100}{15}$

$Z = 0.5$

$Z = 0.5$ has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 probability that the president will have an IQ of at least 107.5.

Probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

First, we find the probability of a single person having an IQ of at least 130, which is 1 subtracted by the p-value of Z when X = 130. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{130 - 100}{15}$

$Z = 2$

$Z = 2$ has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

Now, we find the probability of at least one person, from a set of 2, having an IQ of at least 130, which is found using the binomial distribution, with p = 0.0228 and n = 2, and we want:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.9772)^{2}.(0.0228)^{0} = 0.9549$

$P(X \geq 1) = 1 - P(X = 0) = 0.0451$

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

What is the probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130?

0.3085 probability that the president will have an IQ of at least 107.5.

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Independent events, so we multiply the probabilities.

0.3082*0.0451 = 0.0139

8 0

3 years ago

Select the correct answer. Simplify. 198 49√2 OB. 7√2 OC. 2√7 OD. 14√7​

Select the correct answer. Simplify. 198 49√2 OB. 7√2 OC. 2√7 OD. 14√7