All categories

2 years ago

Train tickets cost £7.93 how much would 4 train tickets cost?

Mathematics

2 answers:

maks197457 [2]2 years ago

6 0

Answer:

7.93×4=31.72.if answer is correct pls follow me

Step-by-step explanation:

the reason is because, if one train ticket cost 7.93 then 4 ticket is going to be multiplied

andrezito [222]2 years ago

3 0

Answer:

£31.72

Step-by-step explanation:

This is a multiplication problem.

1 ticket costs £7.93; 4 tickets cost 4 times £7.93.

4 × £7.93 = £31.72

You might be interested in

Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,

Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

$\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$

In order to use t*, we need to check conditions for using a t-distribution first.

Random for both samples -- NOT STATED in the problem ∴ proceed with caution!
Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
Normality: CLT is not met; n < 30 for both locations A and B ∴ proceed with caution!

Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.

Solve for t*:

We need the tail area first.

$\displaystyle \frac{1-.9}{2}= .05$

Next we need the degree of freedom.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

df for A: 13 - 1 = 12
df for B: 18 - 1 = 17
df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.

t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

$\overline {x}_A=39$
$s_A=8$
$n_A=13$
$\overline {x}_B = 55$
$s_B=2$
$n_B=18$
$t^{*}=-2.015$

Substitute the variables into the formula: $\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$ .

$39-55 \ \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}$

Simplify this expression.

$-16 \ \pm \ -2.015 (\sqrt{5.1453} \ )$
$-16 \ \pm \ 3.73139$

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

$(-20.5707,-11.4293)$

If we want to interpret the confidence interval of (-20.5707, -11.4293), we can say...

We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.

5 0

2 years ago

What is the perimeter of a regular heptagon if one side measures 3 inches

svetlana [45]

What's a regular heptagon? "Hept-" means seven, so a "heptagon" is a seven-sided shape. A "regular" figure's sides are all the same length. So, each of the 7 sides are the same length.

Remember, perimeter is the sum of the lengths of all the sides in a polygon. We know one side measures three inches, so each of the others must also measure 3 inches. 3+3+3+3+3+3+3=3*7=21 inches.

Answer: 21 inches

7 0

3 years ago

WILL GGIVE BRAINLIEST!!!

Citrus2011 [14]

(3x+6)(2x^2), using the distributive property, equals 2x^2*3x+2x^2*6. We multiply the 2 with the coefficients and add a power of x if multiplied by x, getting 6x^3+12x^2

3 0

3 years ago

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 37 o

just olya [345]

Answer:

a) 68 % will lie between 30 and 44 ounces

b) between 23 and 44 ounces will lie 81,5 %

Step-by-step explanation: See Annex

a) Normal Distribution N ( 37, 7)

The Empirical Rule establishes that 68 % of values will be at

μ ± 1 σ where μ is the mean and σ the standard deviation

Then: 37 - 7 = 30 and 37 + 7 = 44

68 % of the values will lie between 30 and 44 ounces

b) And between 23 and 44 we should find:

We have 95 % of values between

μ ± 2*σ

In our case to the left of the value (mean 0 ) and up to the value 23 we get 95/2 = 47,5 % and to the right of the value (mean 0 ) and up to 44 we half 68/2 = 34 %

Then between 23 and 44, we have 47,5 + 34 = 81,5 %

8 0

3 years ago

First four terms of the sequence an = 8 - 2n with formula

kramer

Answer:

6, 4, 2, 0

Step-by-step explanation:

To find the first 4 terms, substitute n = 1, 2, 3, 4 into the n th term formula, that is

a₁ = 8 - 2(1) = 8 - 2 = 6

a₂ = 8 - 2(2) = 8 - 4 = 4

a₃ = 8 - 2(3) = 8 - 6 = 2

a₄ = 8 - 2(4) = 8 - 8 = 0

The first 4 terms are 6, 4, 2, 0

3 0

4 years ago

Read 2 more answers