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steposvetlana [31]
2 years ago
13

If 2^2^x = 2^3 what is the value of x

Mathematics
2 answers:
tino4ka555 [31]2 years ago
8 0

Answer:

\dfrac 32

Step-by-step explanation:

~~~~~~~2^{2x} = 2^3\\\\\implies \ln\left(2^{2x} \right)  = \ln (2^3)\\\\\implies 2x \ln(2) = 3 \ln(2) \\\\\implies 2x = 3\\\\\implies x = \dfrac 32

katrin [286]2 years ago
5 0

Answer:

B

Step-by-step explanation:

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Tyler got 1/(18 +1) = 1/19 of the 1995 votes, so 1995/19 = 105 votes.
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3 years ago
Slope -7 and​ y-intercept ​(0,​9)
faust18 [17]

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y=-7x+9

Step-by-step explanation:

 

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The area of ​​the rectangle is equal to the product of the base times the height. What is the measure of the area of ​​the recta
myrzilka [38]

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A rectangle is a good, simple shape to begin with. The area of a rectangle is equal to the product of the length of its base and the length of its height. The height is a segment that is perpendicular to the base. For a rectangle, the base and height are often called the "length" and the "width", and sometimes the height is referred to as the "altitude."

Step-by-step explanation

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8 0
3 years ago
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z < 3) = 0.99865

 P(X bar <= 30.25) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

                                                                                       = 0.0214

                                       

7 0
3 years ago
What is the solution to this system of linear equations? 7x – 2y = –6 8x y = 3 (–6, 3) (0, 3) (1, –5) (15, –1)
erik [133]

Answer:

(0,3)

Step-by-step explanation:

we have

7x-2y=-6 ----> equation A

8x+y=3 ----> equation B

Multiply the equation B by 2 both sides

2(8x+y)=2*3

16x+2y=6 ------> equation C

Adds equation A and equation C

7x-2y=-6\\16x+2y=6\\--------\\7x+16x=-6+6\\23x=0\\x=0

Find the value of y

7(0)-2y=-6

-2y=-6

y=3

the solution is the point (0,3)

3 0
3 years ago
Read 2 more answers
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