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Tanya [424]
3 years ago
12

Allie, Ben, and Cliff plant ceilings in the neighborhood park. Ali plans 40% of the total number of ceiling, then place 45% of t

he total number of seed wings, and Cliff plans the rest of the siblings. If Cliff +84 siblings how many seedling do the three boys play together
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

The number of seedlings the three boys planted together is 560 seedlings

Step-by-step explanation:

The possible information in the question are;

Percentage of the seedlings planted by Ali = 40%

Percentage of the seedling planted by Ben = 45%

The percentage of the seedling planted by Cliff = The rest of the seedling

The number of seedling planted by Cliff = 84 siblings

Therefore, the percentage of the seedling planted by Cliff = 100% - 45% - 40% = 15%

Given that Cliff planted 15% of the seedlings, we have;

15% of seedlings Cliff planted = 84

Let X = the total number of seedlings

15/100 × X = 0.15×X = 84

X = 84/0.15 = 560

The total number of seedlings = The number of seedlings the three boys planted together = 560 seedlings.

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Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

   = 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

  = 20.93304

The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

  = 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

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Question 6 (4 points)
riadik2000 [5.3K]

Answer:

Interior Angles: 3, 4, 5, 6

Exterior Angles 1, 2, 7, 8

Hope this helps!

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Answer:

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7 0
3 years ago
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Line e has a slope of -2/9. line f is perpendicular to e. what is the slope of f
choli [55]

Answer:

9/2

Step-by-step explanation:

In order to find the slope of a line that is perpendicular to another line, you must find the opposite and reciprocal of that slope. So, you have 2/9, and then 9/2.

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