Need help with this question about amplitude

Mathematics

1 answer:

lesantik [10]1 year ago

4 0

Step-by-step explanation:

the amplitude is the height of the wave.

like with sound - the further away you are, the lower the volume of the sound (as the sound volume is the indicator of the amplitude of a sound wave, or the brightness of a light is the indicator of the amplitude of a light wave).

the same for any other type of wave (like the seismic wave of an earthquake).

so, the larger the distance, normally the smaller the amplitude.

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The table shows population statistics for the ages of Best Actor and Best Supporting Actor winners at an awards ceremony. The di

babunello [35]

Solution:

$Z score =\frac{X-\sigma}{\mu}$

1. For Best Actor

$X_{1}$ = 59 years

$\sigma=7.3, \mu=42.0$

Z, Score for best actor named, $Z_{1}$

$Z_{1}=\frac{59-7.3}{42}\\\\Z_{1}= \frac{51.7}{42}\\\\Z_{1}=1.23095\\\\ Z_{1}=1.24$

Z-Score for best actor = 1.24

2. Z , Score for best supporting actor , called $Z_{2}$

$X_{2}$ =49 years

$\sigma=15, \mu=49.0$

$Z_{2}=\frac{49-15}{49}\\\\Z_{2}= \frac{34}{49}\\\\Z_{2}=0.6938\\\\ Z_{2}=0.70$

Z-Score for best supporting actor = 0.70

Z-Score is usually , the number of standard deviations from the mean a point in the data set is.

3. As, $Z_{1}=1.24$

So, we can say that,Option (B) The Best Actor was more than 1 standard deviation above is not unusual.

4.As, $Z_{2}=0.70$

So, we can say that,Option(A) The Best Supporting Actor was less than 1 standard deviation below, is not unusual.

8 0

2 years ago

trisha started out with 40,000 miles on her car and drove exactly 800 miles a week. After how many weeks did she have 44,800 mil

Yuri [45]

Since she started out with 40,000 miles, you have to subtract that from 44,800 miles. you end up with 4,800 miles. you then divide 4,800 miles by 800 miles and you end up with 6 as your answer.

4 0

3 years ago

Identify all of the following solutions of square root of x plus 14 end root plus 2 equals x.

BabaBlast [244]

$\bf \sqrt{x+14}+2=x\implies \sqrt{x+14}=x-2\impliedby \textit{squaring both sides}
\\\\\\
(\sqrt{x+14})^2=(x-2)^2\implies x+14=x^2-4x+4
\\\\\\
0=x^2-5x-10\impliedby \textit{now, using the quadratic formula}
\\\\\\
x=\cfrac{5\pm\sqrt{(-5)^2-4(1)(-10)}}{2(1)}\implies x=\cfrac{5\pm\sqrt{25+40}}{2}
\\\\\\
x=\cfrac{5\pm \sqrt{65}}{2}\implies x=
\begin{cases}
\cfrac{5+ \sqrt{65}}{2}\\\\
\cfrac{5- \sqrt{65}}{2}
\end{cases}$