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ivann1987 [24]
2 years ago
5

Does anyone know what 1-4/8-1/8 is

Mathematics
2 answers:
Dennis_Churaev [7]2 years ago
6 0

\bf{1-\dfrac{4}{8}-\dfrac{1}{8}  }

Reduce the fraction 1/4 to its lowest expression by extracting and canceling 4.

\bf{1-\dfrac{1}{2}-\dfrac{1}{8}  }

Convert 1 to the fraction 2/2.

\bf{\dfrac{2}{2}-\dfrac{1}{2} -\dfrac{1}{8}   }

Since 2/2 and 1/2 have the same denominator, subtract their numerators to subtract them.

\bf{\dfrac{1-2}{2}-\dfrac{1}{8}   }

Subtract 1 from 2 to get 1.

\bf{\dfrac{1}{2}- \dfrac{1}{8} }

Convert 1/2 and 1/8 to fractions with denominator 8.

\bf{\dfrac{4}{8}-\dfrac{1}{8}  }

Since 4/8 and 1/2 have the same denominator, subtract their numerators to subtract them.

\bf{\dfrac{4-1}{8} \ \ \to \ \ \ Subtract }

Subtract 1 from 4 to get 3.

\bf{\dfrac{3}{8} \ \ \to \ \ \ Answer }

\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}

san4es73 [151]2 years ago
5 0

Answer ⇒ \frac{3}{8}

Step-by-step explanation:

1-\frac{4}{8} -\frac{1}{8}

⇒ 1-\frac{1}{2} -\frac{1}{8}

⇒ \frac{1}{2} -\frac{1}{8}

⇒ \frac{4}{8} -\frac{1}{8}

⇒ \frac{3}{8}

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cluponka [151]

Answer:

x=6

Step-by-step explanation:

5x - 8 = 3x + 4

    +8         +8

5x=3x+12

-3x  -3x

2x=+12

/2    /2

x=6

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2 years ago
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Alecsey [184]
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Divide 1920 by 40
Then multiply the number by 2
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The sum of the cube of a number and 12
Black_prince [1.1K]
Let the "number" be n.

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3 years ago
The table below shows the number of invertebrates found in a tide pool. Find the ratio of crabs to the total number of invertebr
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Hope this helps!
4 0
3 years ago
determine the point of intersection of the following pair of lines ............2x-3y-4=-13 and 5x=-2y+25. 3x+2y-7=0 and 2x=12-5y
grandymaker [24]

Answer:

  1. (x, y) = (3, 5)
  2. (x, y) = (1, 2)

Step-by-step explanation:

A nice graphing calculator app makes these trivially simple. (See the first two attachments.) It is available for phones, tablets, and as a web page.

__

The usual methods of solving a system of equations involve <em>elimination</em> or <em>substitution</em>.

There is another method that is relatively easy to use. It is a variation of "Cramer's Rule" and is fully equivalent to <em>elimination</em>. It makes use of a formula applied to the equation coefficients. The pattern of coefficients in the formula, and the formula itself are shown in the third attachment. I like this when the coefficient numbers are "too messy" for elimination or substitution to be used easily. It makes use of the equations in standard form.

_____

1. In standard form, your equations are ...

  • 2x -3y = -9
  • 5x +2y = 25

Then the solution is ...

  x=\dfrac{-3(25)-(2)(-9)}{-3(5)-(2)(2)}=\dfrac{-57}{-19}=3\\\\y=\dfrac{-9(5)-(25)(2)}{-19}=\dfrac{-95}{-19}=5\\\\(x,y)=(3,5)

__

2. In standard form, your equations are ...

  • 3x +2y = 7
  • 2x +5y = 12

Then the solution is ...

  x=\dfrac{2(12)-5(7)}{2(2)-5(3)}=\dfrac{-11}{-11}=1\\\\y=\dfrac{7(2)-12(3)}{-11}=\dfrac{-22}{-11}=2\\\\(x,y)=(1,2)

_____

<em>Note on Cramer's Rule</em>

The equation you will see for Cramer's Rule applied to a system of 2 equations in 2 unknowns will have the terms in numerator and denominator swapped: ec-bf, for example, instead of bf-ec. This effectively multiplies both numerator and denominator by -1, so has no effect on the result.

The reason for writing the formula in the fashion shown here is that it makes the pattern of multiplications and subtractions easier to remember. Often, you can do the math in your head. This is the method taught by "Vedic maths" and/or "Singapore math." Those teaching methods tend to place more emphasis on mental arithmetic than we do in the US.

7 0
3 years ago
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