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Elza [17]
1 year ago
7

Question 1 - A point M on a segment with endpoints X (1,-2) and Y (10,3) partitions the segment in a 5:1 ratio Find M

Mathematics
1 answer:
Readme [11.4K]1 year ago
7 0

The value of M based on the information about the segment is

<h3>How to find the value?</h3>

Since segment XY is divided in the ratio 5:1, it is divided into 6 equal sections. (6 = 5+1). As we move along XY from X to Y, x increases by 9, and y increases by 5. M is the point on XY that is 5/6 of the way from X to Y.

  • x-coordinate of M = 1 + (5/6)(9) = 1 + 7.5 = 8.5
  • y-coordinate of M = -2 + (5/6)(5) = -2 + 4 1/6 = 2 1/6

Therefore, M = (8 1/2, 2 1/6).

Learn more about segment on:

brainly.com/question/2437195

#SPJ1

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Ostrovityanka [42]

Answer:

5n/2

Step by Step Explanation:

Well, 5 times a number (the number is a variable so you just put it next to the 5) and 2 so you are dividing by 2 and the fraction bar is the same as division so 5n/2

4 0
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Divide (-7x+x^2+15)\(-3+x)
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The answer would be x-4+ 3/x-3
8 0
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Solve y∕2.5 = 5 for y.
Radda [10]

Answer:

D)12.5

Step-by-step explanation:

y/2.5=5

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3 years ago
Maria had 6 feet of ribbon. She will cut the ribbon into pieces that are 2/3 of a foot long. How many pieces of ribbon will Mari
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Answer:

2/3 x 9 = 18 divided by 3 = 6

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4 0
2 years ago
what is the slope intercept form of the linear equation with a graph that passes through (-2,2) and is perpendicular to the grap
qwelly [4]

Hey there!!

Steps to get into equation which is perpendicular:

  • Change the slope
  1. The slope of a perpendicular line is always negative reciprocal.
  • Take the point and get that into point-slope form.
  1. y - y = m ( x - x )
  • Convert this equation into slope-intercept form.

'm' is the slope.

We have the slope as 1/3

The perpendicular slope would be -3.

Point slope:

The point = (-2,2)

y - 2 = -3( x - (-2) )

y - 2 = -3(x+2)

y - 2 = -3x -6

Adding 2 on both sides:

y = -3x - 4

<em>Hence, the equation would be : </em>

<u><em>y = -3x - 4 </em></u>

Hope it helps!


7 0
3 years ago
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