The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59
This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.
The n-th term is
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
= 29 + 320
= 349
Answer: a₃₃ = 349
Answer: 1. the negative of the conclusion is true
The maximum radius of each ball is 3.33 cm.
<h3>What is a Cylinder?</h3>
A cylinder is a three-dimensional figure which is made of two parallel circular bases separated at a certain distance by a curved surface of the same radius as that of the bases.
A 20 cm nail perfectly fits the cylinder.
So the height of the cylinder = 20cm.
A sphere is a three-dimensional geometrical figure analogous to a circle. All the points of the sphere are at the same distance from the center.
If 3 spheres have to be fitted inside the cylinder,
The sum of the diameter of the spheres will be equal to the height of the cylinder.
The spherical balls are identical and so will have the same diameter
Let the maximum diameter of the sphere that can fit in the cylinder is d cm
Then,
d + d + d = 20
3d = 20
d = 20/3 = 6.67 cm
r = 3.33 cm
The maximum radius that the spheres can have to fit in the cylinder is 3.33 cm.
To know more about Cylinder
brainly.com/question/16134180
#SPJ1
Answer:
The equation above represents the total time the play director spent preparing for a play.
Step-by-step explanation:
The time spent by the play director for preparing for a play is, 190 hours.
Of these 190 hours, the director spent varying amounts of time attending 35 rehearsals for the play.
Let the varying amounts of time be denoted by, <em>x</em>.
The director also spent 3/4th of an hour, i.e. 45 minutes, on other responsibilities related to the play.
The equation provided is:
The equation above represents the total time the play director spent preparing for a play.
