Answer:
8 books
Step-by-step explanation:
5+3=8
Answer:
The average amount he paid over 3 days is $15.47.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
Answer:
(½x+½y)²=6
Step-by-step explanation:
x^2 + y^2 = 14, xy=5
(A+B)^2=A^2 +2AB+B^2... (*)
(1/2x+1/2y)^2 =(*)
(1/2x)^2 +2(1/2x)(1/2y)+(1/2y)^2 =
1/4x^2 +1/2xy+1/4y^2=
1/4(x^2 +y^2) +1/2(xy)=
1/4*14+1/2*5=
14/4+5/2=
14/4+10/4=
24/4=6
let me know if I'm wrong.
Answer:
Isosceles Triangle; Acute Triangle
Step-by-step explanation:
Review your definitions of the different types of triangles:
acute triangle- a triangle that has three acute (less than 90 degrees) angles
obtuse triangle- a triangle that has an obtuse (greater than 90 degrees) angle.
right triangle- a triangle that had one right (90 degrees) angles
isosceles triangle- a triangle with two congruent sides and one unique side and angle.
equilateral triangle- a triangle with three congruent sides and three congruent angles.
scalene triangle- a triangle with no congruent sides and no congruent angles.
With these definitions, we can classify ΔPQR as an isosceles acute triangle.
