Question

The midpoint of AB given A (3, -12) and B (-1, -2) is (x, y). What are the values of x and y?

Answer 1

Answer:

(1, - 7 )

Step-by-step explanation:

using the midpoint formula

given endpoints (x₁, y₁ ) and (x₂, y₂ ) , then

midpoint = ( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

here (x₁, y₁ ) = A (3, - 12 ) and (x₂, y₂ ) = B (- 1, - 2 )

midpoint = ( $\frac{3-1}{2}$ , $\frac{-12-2}{2}$ ) = ( $\frac{2}{2}$ , $\frac{-14}{2}$ ) = (1, - 7 )

Answer 2

Step-by-step explanation:

$x_{m} , y_{m} \: = ( \frac{x _{1} + x_{2} }{2} ,\frac{y _{1} + y_{2} }{2})$

x1 = 3, x2 = (-1)

y1 = (-12), y2 = (-2)

$x_{m} , y_{m} \: = ( \frac{3+ ( - 1) }{2} ,\frac{( - 12)+ ( - 2) }{2})$

$x_{m} , y_{m} \: = ( \frac{3 - 1 }{2} ,\frac{( - 12) - 2 }{2})$

$x_{m} , y_{m} \: = ( \frac{2 }{2} ,\frac{- 14 }{2})$

$x_{m} , y_{m} \: = 1 ,( - 7)$