Use a graphing calculator to approximate the vertex of the graph of the parabola defined by the following

Mathematics

1 answer:

gregori [183]1 year ago

8 0

Answer:

(1/4, 5 7/8)

Step-by-step explanation:

The vertex is the extreme point of the graph. Here, it is a minimum.

For this quadratic function, a graphing calculator can tell you exactly what the vertex is. (No approximation is required.)

The graphing calculator in the attachment shows the vertex is ...

(0.25, 5.875) = (1/4, 5 7/8)

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Find the area of each parallelogram plz help

xxTIMURxx [149]

Answer: The area of the parallelogram is:
_______________________________________________________
$\frac{9393}{8}$ in² = 1174 ⅛ in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
A = base * height = b * h ;

From the figure (from the actual "question"):
_______________________________________
b = 50.5 in.

h = 23.25 in.
____________________________________________________________
Method 1) A = b * h =

= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 ⅛ .
____________________________________________________________
Method 2) A = b * h =

= (50 ½ in) * (23 ¼ in) =

= ( $\frac{101}{2}$ in) * ( $\frac{93}{4}$ in) ;
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Note: "50 ½ " = [(50*2) + 1 ] / 2 = $\frac{101}{2}$ ;

Note: "23 ¼ " = [(23*4) + 1 ] / 4 = $\frac{93}{4}$ ;
____________________________________________________________
→ A = ( $\frac{101}{2}$ in) * ( $\frac{93}{4}$ in) ;

→ A = $\frac{(101*93)}{(2*4)}$ in² = $\frac{9393}{8}$ in² ;

→ A = (9393/8) in² =

→ A = $\frac{9393}{8}$ in² = 1174 ⅛ in² = 1174.125 in² .
________________________________________________________

5 0

2 years ago

For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year.

lidiya [134]

Answer: $ 125987.80

Step-by-step explanation:

Given: The value, V(t) of $393,000 worth of assets after t years, that depreciate at 15% per year, is given by the formula

$V (t)=V_o(b)^t$ , here $V_o$ is the initial asset value and b is the multiplicative decay factor.