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2 years ago

If p() = x2 - 1 and q(x) - 5(x-1), which expression is equivalent to (p - q)(x)?

Mathematics

1 answer:

TiliK225 [7]2 years ago

7 0

Answer:

$\text{If p(x) = x2 - 1 and q(x) = 5(x - 1), the expression which is equivalent to}$ $\text{ (p - q)(x) is (x2 - 1) - 5(x - 1).}$

Step-by-step explanation:

Given:

p(x) = 2x2 - 1
q(x) = 3(x - 1)

To find:

(p - q)(x)

We know:

(p - q)(x) = p(x) - q(x)

Substitute

(2x^2 - 1) - 3(x - 1)

$\text{Therefore, the expression equivalent to (p - q)(x) is (2x2 - 1) - 3(x - 1).}$

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3 years ago

If Tara spend $219 a month for her car payment and she makes $3,200 a month , what percent of her monthly income is spent on her

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Answer:

6.84%

Step-by-step explanation:

we know that

In this problem

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3 years ago

The data in the tables below were collected from first year students at a community college. The variable is "number of credit c

Oliga [24]

Solution :

It is given that P(x) is said to be complete or proper probability distribution if it satisfies the following two ways :

1. $P(x) \geq 0$

2. $\sum_z P(x) = 1$

Now consider,

$\sum_z P(x) = 1$

⇒ $P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)=1$

⇒ $0.61+T+0.14+0.01+0.01+0.03=1$

⇒ $0.8+T=1$

⇒ $T=1-0.8$

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Thus, option (c) is correct.

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3 years ago

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Mashcka [7]

Answer:

a) P(X<50)=0.9827

b) P(X>47)=0.4321

c) P(-1.5<z<1.5)=0.8664

Step-by-step explanation:

We will calculate the probability based on a random sample of one moped out of the population, normally distributed with mean 46.7 and standard deviation 1.75.

a) This means we have to calculate P(x<50).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

$z=\dfrac{X-\mu}{\sigma}=\dfrac{50-46.7}{1.75}=\dfrac{3.7}{1.75}=2.114\\\\\\P(X$

b) We have to calculatee P(x>47).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

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$z=\dfrac{(\mu+1.5\sigma)-\mu}{\sigma}=\dfrac{1.5\sigma}{\sigma}=1.5$

So the probability that maximum speed differs from the mean value by at most 1.5 standard deviations is P(-1.5<z<1.5):

$P(-1.5$

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