Answer:
The graph is attached.
Step-by-step explanation:
The range of this data is the highest value, 22, subtracted by the lowest value, 1: 22-1 = 21.
Using boundaries, the first bar would go from 0.5-3.5; the second from 3.5-6.5; the third from 6.5-9.5; the fourth from 9.5-12.5; the fifth from 12.5-15.5; the sixth from 15.5-18.5; the seventh from 18.5-21.5; and the eighth from 21.5-24.5.
The frequency of the first bar, its height, would be 1; the height of the second bar is 2; the height of the third bar is 3; the height of the fourth bar is 2; the height of the fifth bar is 3; the height of the sixth bar is 1; the height of the seventh bar is 1; and the height of the eighth bar is 1.
Answer:
m∠J = 45° , m∠I = 45° and m∠M = 90°
And the ΔJIM is an isosceles right angled triangle.
Step-by-step explanation:
(a). In ΔJIM,
∠J = 2x + 15,
∠I = 5x - 30, and
∠M = 6x
Now, using angle sum property of a triangle that sum of all the angles in a triangle is 180°
⇒ ∠J + ∠I + ∠M = 180°
⇒ 2x + 15 + 5x - 30 + 6x = 180°
⇒ 13x -15 = 180°
⇒ 13x = 195
⇒ x = 15
Therefore, m∠J = 45° , ∠I = 45° and m ∠M = 90°
(b). Now, ΔJIM is a right angled triangle right angled at M.
Also, ∠J = ∠I = 45°
So, JM = IM ( because in a triangle sides opposite to equal angles are equal)
So, ΔJIM is an isosceles triangle because its two sides are equal.
Hence, ΔJIM is a right angled isosceles triangle right angled at M.
Answer: a. g(x) = 3^x + 2 b. y = 3 c. same graph but shifted two units up
Step-by-step explanation:
First you plug in the variables:
(-3)(2)+(6)(-3)(4)
Multiply:
-6+(-18)(4)
-6+-72
Add and your answer comes out to be:
-78
Ok, since the ice rink is a square (which has equal sides) if you multiply 404 times four because a square has 4 sides which is equal to 1616 the perimiter is 1616 sqf
404*4= 1616 p= 1616sq
