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wel
2 years ago
5

How do I solve x² - 10x-3=0

Mathematics
1 answer:
evablogger [386]2 years ago
3 0

Answer:

x = 5±2√7

Step-by-step explanation:

This quadratic cannot be factorised via the factorisation method, so we use the quadratic formula :

x = \frac{-b + \sqrt{b^{2} -4ac} }{2a} or x = \frac{-b - \sqrt{b^{2} -4ac} }{2a}

(The reason I did 2 equations is because brainliest does not allow me to do the ± in the equation insert thing )

x = \frac{-(-10) + \sqrt{-10^{2} -4(1)(-3)} }{2(1)} or x = \frac{-(-10) - \sqrt{-10^{2} -4(1)(-3)} }{2(1)}

x = \frac{10  + \sqrt{100+12} }{2} or x= \frac{10  - \sqrt{100+12} }{2}

x = \frac{10  + {4\sqrt{7}} }{2} or x = \frac{10  -  {4\sqrt{7}} }{2}

x = 5+2\sqrt{7} or x = 5 -2\sqrt{7}

Hope this helped and brainliest please

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Answer:

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Step-by-step explanation:

Since the zeros of the equation are -3 and 5+i, hence the factors of the polynomial in x is (x+3) and (x-(5+i))

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<u>Answer:</u>

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