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QveST [7]
2 years ago
5

Geometry please help!

Mathematics
1 answer:
o-na [289]2 years ago
6 0

Answer:

x = 3

Step-by-step explanation:

Angle S and Angle T are consecutive interior angles. Therefore, we know that T + S = 180°.

First, we need to solve for T, and since angles S and T are consecutive interior angles, we know that T + S = 180°. If we reorganize the equation to include the things we know (S = 105°), then we get 180° - 105° = 75°. So T is 75°.

Now, we use T = 75° and the information given to us in the picture to set up an equation. 75 = 24x + 3. Now, we can find x by isolating it. Do this by:

1) Subtracting 3 from both sides to give you 72 = 24x. We do this to get rid of the 3 from the "x side", but we must also do it to the other to keep the equation true. This moves the 3 from the "x side" to the other since we're trying to isolate x.

2) Divide 24 by both sides to get 3 = x. We use the same logic as we did for 3, except this time we divide since that's the opposite of multiplying.

In conclusion, x = 3.

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PART A
General formula of quadratic equation
ax² + bx + c = 0
To find the discriminant of the quadratic equation shown above, use this following formula.
d = \sqrt{b^{2}-4ac}

There is a quadratic equation below
x² - 16x + 4 = 0
therefore
a = 1
b = -16
c = 4

Plug in the numbers to the formula
d = \sqrt{b^{2}-4ac}
d = \sqrt{(-16)^{2}-4(1)(4)}
d = \sqrt{(256-16}
d = \sqrt{240}

Simplify
d = \sqrt{16*15}
d = 4 \sqrt{15}
The value of the discriminant is 4√15

PART B
If the discriminant is less than zero (negative), the quadratic equation has imaginary solution.
If the discriminant is equal to zero, the quadratic equation has only one solution.
If the discriminant is more than zero (positive), the quadratic equation has two real solutions.

Because the discriminant of the quadratic equation is 4√15 and it's positive, <u>the quadratic equation has two real solutions.</u>
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