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Gnoma [55]
2 years ago
5

a train starting from rest moves with uniform acceleration of 5 m/s2 .find its velocity when it has travelled a distance of 1 km

Mathematics
1 answer:
Degger [83]2 years ago
7 0

The velocity of a train starting from rest moves with a uniform acceleration of 5 m/s2 would be 100 m/s.

Acceleration = 5 m/s2

Distance, s = 1 km = 1000m

Intital velocity, u=0 m/s

<h3>What is the first equation of motion?</h3>

We know that, Newton's equation of motion,

s = ut+ 1/2 at^2

1000 = 0 + 1/2 x 5 x t^2

1000 = 5/2 x t^2

2000/ 5 = t^2

t = 20 s

Also,a = (v-u)/t

5 = v-0/20

100 = v

v = 100 m/s

Hence, the velocity of a train starting from rest moves with a uniform acceleration of 5 m/s2 would be 100 m/s.

Learn more about velocity here;

brainly.com/question/3491339

#SPJ1

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<h2>Hey there! </h2>

<h3>The answer is: </h3>

<h3>Option 'B' </h3>

\sqrt{19}  +  \frac{7}{2}

<h2>BECAUSE root 19 is irrational. </h2>

<h2>Hope it help you </h2>
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3 years ago
Drag each pair of numbers to show if their greatest common factor (GCF) is less than 2, equal to 2, equal to 3, or greater than
TEA [102]

Answer:

GCF < 2 : 2 and 7, 12 and 13

GCF = 2 : 2 and 6

GCF = 3 : 3 and 6

GCF > 3 : 4 and 12, 6 and 18

Step-by-step explanation:

The greatest common Factor (GCF) of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

(a) 2 and 7: Both 2 and 7 are prime numbers, therefore the GCF of 2 and 7 is 1 which is less than 2.

(b) 2 and 6: Both 2 and 6 are even numbers, therefore the GCF of 2 and 6 is 2.

(c) 4 and 12: Both 4 and 12 are even numbers and multiple of 4, therefore the GCF of 4 and 12 is 4 which is greater than 3.

(d) 12 and 13: 13 is a prime number, therefore the GCF of 12 and 13 is 1 which is less than 2.

(e) 6 and 18: Both 6 and 18 are even numbers and multiple of 6, therefore the GCF of 6 and 18 is 6 which is greater than 2 and greater than 3.

(f) 3 and 6: Both are multiple of 3, therefore the GCF of 3 and 6 is 3.

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3 years ago
Examine the two similar triangles below solve for y need by 11:59 for final exam
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Answer:

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Step-by-step explanation:

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Find the product of -5x²y⁴ and 3xy³​
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Answer: -15x^3y^7

Step-by-step explanation:

 

-5x^2y^4(3xy^3)  

Multiplty the coefficients

Multiply the x terms

and fianally multiply the y terms  

-5(3) = -15

x^2 * x = x^3

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= -15x^3y^7

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