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german
3 years ago
15

Dr. Potter provides vaccinations against polio and measles. Each polio vaccination multi-dose vial consists of 44 individual dos

es, and each measles vaccination multi-dose vials consists of 22 individual doses. Last year, Dr. Potter used a total of 60 multi-doses vials that consisted of a total of 2024 individual doses. How many individual polio and measles vaccinations did Dr. Potter give, respectively?
Mathematics
2 answers:
Anastaziya [24]3 years ago
4 0
The correct answer for the question that is being presented above is this one: "A (28,32)." Dr potter provides vaccinations against polio and measles. Each polio vaccination multi-dose vial consists of 44 individual doses, and each measles vaccination multi-dose consists of 22 individual doses. Dr. Potter give 28 and 32 individual polio and measles vaccinations, respectively.<span>
</span>
Serggg [28]3 years ago
4 0

Answer E. autism

Step-by-step explanation:

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4 years ago
When I sit and watch my students take exams, I often think to myself "I wonder if students with bright calculators are impacted
hodyreva [135]

Answer:

There is a difference between the two means.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The mean exam scores of my SAT 215 students with colorful calculators are same as the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: The mean exam scores of my SAT 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

Assume that the significance level of the test is, <em>α</em> = 0.05. Also assuming that the population variances are equal.

The decision rule:

A 95% confidence interval for mean difference can be used to determine the result of the hypothesis test. If the 95% confidence interval contains the null hypothesis value, i.e. 0 then the null hypothesis will not be rejected.

The 95% confidence interval for mean difference is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

Compute the pooled standard deviation as follows:

S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}} {n_{1}+n_{2}-2}}}=\sqrt{\frac{(49-1)(4.7)^{2}+(38-1)(5.7)^{2}}{49+38-2}}=5.16

The critical value of <em>t</em> is:

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (49+38-2)}=t_{0.025, 85}=1.984

*Use a <em>t</em>-table.

Compute the 95% confidence interval for mean difference as follows:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

     =(84-87)\pm 1.984\times 5.16\times \sqrt{\frac{1}{49}+\frac{1}{38}}

     =-3\pm 2.133\\=(-5.133, -0.867)\\\approx(-5.13, -0.87)

The 95% confidence interval for mean difference is (-5.13, -0.87).

The confidence interval does not contains the value 0. This implies that the null hypothesis will be rejected at 5% level of significance.

Hence, concluding that the mean exam scores of my STA 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators.

7 0
4 years ago
WILL mark BRAINLIEST <br> WHICH OF THE FOLLOWING COULD BE THE EQUATION OF THE FUNCTION BELOW?
AysviL [449]

Answer:

y = 0.5cos(4(x+π/2)) -2

Step-by-step explanation:

The centerline of the oscillation is at -2, so only the 2nd and 4th choices are viable.

The multiplier of x is computed from (2π)/period. One period is π/2, so the multiplier of x is ...

... 2π/(π/2) = 4 . . . . . matching the 2nd selection.

The horizontal offset in the second equation (π/2) is of no consequence, as it is one full period of the function.

The peak-to-peak amplitude of the oscillation is 1 unit, so the multiplier of the cosine function (which usually has a peak-to-peak value of 2 units) is 0.5. Every offered answer has that characteristic.

The appropriate choice is the 2nd one:

... y = 0.5cos(4(x+π/2)) -2

3 0
3 years ago
Read 2 more answers
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