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nevsk [136]
2 years ago
8

A coordinate grid with 2 lines. The first line is labeled g(x) and passes through the points (negative 3, 0) and (0, 2). The sec

ond line is labeled f(x) and passes through the points (negative 3, 0) and (0, 2). What is the solution to the system of linear equations? (–3, 0) (–3, 3) (0, 2) (3, 1)

Mathematics
1 answer:
Snezhnost [94]2 years ago
6 0

The correct answer is option c i.e. (0, 2)

<h3>What is Linear Equation?</h3>

A linear equation is an algebraic equation where each term has an exponent of 1 and when this equation is graphed, it always results in a straight line.

Here, The solution to this Linear System is already shown by the graph. This is also called the Graph Method. The Solution of this Linear System is this common point in this case, (0,2).

Since each equation is represented by a line. So We have  g(x) for the red line, and f(x) for the blue one. Each line is a set of points, We know that from the Euclidean Geometry and its common point (0,2) solves this system.

Thus, the correct answer is option c i.e. (0, 2)

Learn more about linear equation from:

brainly.com/question/11897796

#SPJ1

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(Area of triangle).
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Your answer is B for this one
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Read 2 more answers
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
stiks02 [169]

Answer:

0.0497 - 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.026

0.0497 + 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.073

The 90% confidence interval would be given by (0.026;0.073)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated proportion for this case is:

\hat p =\frac{322-306}{322}= 0.0497

Represent the proportion of defectives for this case

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.0497 - 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.026

0.0497 + 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.073

The 90% confidence interval would be given by (0.026;0.073)

3 0
3 years ago
S = 4LW + 2WH; S = 168, L = 8, W = 4<br><br> H=
IRISSAK [1]

Answer:

umm check your math book in page 445

Step-by-step explanation:

5 0
3 years ago
Use the Distributive Property to simplify (–5 – c)( –1).
damaskus [11]
It’s the first option, 5 + c
4 0
1 year ago
Read 2 more answers
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