Answer:
Explanation:
Part D
For d, the very first thing you need to do is figure out which one of the steps you are going to use. You have 2 in b^2 + 2, so even if b = 0 the two still matters. It means that you use f(x) = -x + 3 because that's what you use when you have 2 or above.
The second thing you have to realize is that f(x) = -x + 3 has the meaning of what ever you see on the left in the place of x, you put on the right wherever there is an x.
In this case f(b^2 + 2) = -b^2 - 2 + 3 = 1 - b^2
I'm not sure enough to give you an answer for the domain and range, not this time of night.
Answer:
Pretty sure I figured it out, 4/27. I found this by simplifying:
((1/3pi (h - 2/3 h))(4/9 r^2)) / (1/3 pi r^2 h)
Answer:
C. The graph is always positive.
Explanation:
To solve this, it is basically a process of elimination. A is true since the -9 indicates the function was translated down 9 units, making the vertex lie on the y-axis. B is also true because if you look at the equation from 0 to infinity, the y-values increase. D is also correct because when you solve for the zeros, they do end up being 3 and -3, making the only claim that is not true C, the graph is always positive.
