<img src="https://tex.z-dn.net/?f=25x%5E%7B3%7D%20-215x%5E%7B2%7D%20%2B280x" id="TexFormula1" title="25x^{3} -215x^{2} +280x" al

All categories

pychu [463]

2 years ago

t="25x^{3} -215x^{2} +280x" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Firlakuza [10]2 years ago

3 0

Answer:

5x(5x - 8)(x - 7)

Step-by-step explanation:

25x³ - 215x² + 280x =

= 5x(5x² - 43x + 56)

= 5x(5x - 8)(x - 7)

You might be interested in

Solve the inequality please- 21 ≥ 3(a- 7) +9 Thank you so much

Alexeev081 [22]

Answer:

Step-by-step explanation:

+21 +21

-9 -9

÷3 ÷3

8 0

3 years ago

A department store is having a “half price” sale. Which is equivalent to “half price”?

Delvig [45]

Answer:

50% off

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Simplest form<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B5%7D%20-%20%20%5Cfrac%7B3%7D%7B8%7D%20%20" id="TexFormula

raketka [301]

$\frac{3}{5}$ - $\frac{3}{8}$ = $\frac{3 * 8}{5 * 8}$ - $\frac{3 * 5}{8 * 5}$ = $\frac{24}{40}$ - $\frac{15}{40}$ = $\frac{9}{40}$

4 0

3 years ago

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

$\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}$

Taking the RHS, note

$\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}$

Remember that

$\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)$

Therefore,

$\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}$

Once

$\dfrac{\sin(x)}{\cos(x)} = \tan(x)$

Then,

$\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)$

Hence, it is proved

5 0

2 years ago

Ari buying 10 1/2 feet of rope that costs $5.25 per foot.How much will Ari spend?

lapo4ka [179]

Answer:

55.13

Step-by-step explanation:

10×5.25 = 52.50

52.50+2.63= 55.13

8 0

3 years ago