There is a given point (10,3) this shows that when the width (X) is 10, the height (Y) is 3.
On the left side of the graph, they show an equation for the height Hw as being the constant over w ( width).
Using the given point solve for the constant.
Replace Hw with 3 and w with 10:
3 = Constant/10
Solve for the constant by multiplying both sides by 10:
Constant = 3 x 10
Constant = 30
The answer is B.
Answer:
Y=5x + 8
Step-by-step explanation:
The slope of a perpendicular like would be 5
y = 5x + B
-2 = 5(-2)+ B
-2 = -10 + b
b = 8
Y=5x + 8
The average r. of c. of a function f(x) on an interval [a,b] is:
f(b) - f(a)
--------------
b-a
You'll need to apply this to all four of the given functions.
First function: f(x) = x^2 + 3x
a= -2; b= 3
Then the ave. r. of c. for this function on this interval is:
18 - (-2) 20
------------------ = ---------- = 4. y increases by 4 for every unit increase in x.
3-(-2) 5
Do the same thing for the other 3 functions.
Then arrange your four results in descending order (greatest to least).
