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olga2289 [7]
2 years ago
5

le="\sf\large\green{\underbrace{\red{Question*}}}:" alt="\sf\large\green{\underbrace{\red{Question*}}}:" align="absmiddle" class="latex-formula">
Solve for p
\frac{p}{3 }  > 2(p + 7)
​
Mathematics
2 answers:
Elis [28]2 years ago
4 0

Answer:

p < -42 / 5

Step-by-step explanation:

Nuetrik [128]2 years ago
3 0
<h3><u>Solution</u> :</h3>

\implies \:  \sf{ \dfrac{p}{3} > 2(p + 7) } \\  \\ \implies \:  \sf{ \frac{p}{3}  > 2p + 14 } \\  \\ \implies \:  \sf{p> 3( 2p + 14) } \\  \\ \implies \:  \sf{p \: > \:  6p +42} \\  \\ \implies \:  \sf{p - 6p \: > \: 42} \\  \\ \implies \:  \sf{ - 5p \: > \: 42} \\  \\ \implies \: \sf{ - p \: > \:  \dfrac{42}{5} } \\  \\ \implies \:  \red{\bf{ p \:  <  \:   -  \: \dfrac{42}{5} }}

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