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svetoff [14.1K]

2 years ago

8

Y=-8x+1 find the slope and y-intercept in this equation.

1 answer:

vesna_86 [32]2 years ago

5 0

The slope is -8 and the y intercept is 1
the slope is always the number in front of the x and the y intercept is always the number by itself
hope this helps!

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Which expression is equivalent to the area of square A, in square inches?

Setler [38]

Answer:

length of 1 side of A, using the Pyth. Thm. and the dimensions of the other two squares: (side of A)^2 = (10 in)^2 + (24 in)^2. Then:

(side of A)^2 = 100+ 576 in^2 = 676 in^2.

Here I have not bothered to solve for the length of the side of A, since we want the area of square A. But if you do want the side length, find it: sqrt(676) = 26 in. Then the area of A is (26 in)^2 = 676 in^2.

Then the area of square A is (26 in)^2 =

Read more on Brainly.com - brainly.com/question/10676137#readmore

Step-by-step explanation:

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John calipari, head basketball coach for the 2012 national champion University of Kentucky Wildcats, is th ehighest paid coach i

erastovalidia [21]

Answer: Cool!ididnt even no that!

Step-by-step explanation:

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3 years ago

I need help with DE Precalculus, mainly trig identities. Would anyone be willing to zoom or text me to help tutor? Thanks!

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6 0

3 years ago

Please help me!<br> Find the number x such that f(x) =1

STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

$f(x) = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

$1 = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

This has two equations. So, we can separate them into two separate cases. Namely:

$1=-\frac{1}{2}x-1\text{ or } 1=x$

Let's solve for x in each case.

Case I:

We have:

$1=-\frac{1}{2}x-1$

Add 1 to both sides:

$2=-\frac{1}{2}x$

Let's cancel out the fraction by multiplying both sides by -2. So:

$2(-2)=(-2)\frac{-1}{2}x$

The right side cancels:

$-4=x\\$

Flip:

$x=-4$

So, x is -4.

Case II:

We have:

$1=x$

Flip:

$x=1$

This is the solution for our second case.

So, we have:

$x_1=-4\text{ or } x_2=1$

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

$x_1=-4\text{ or } x_2=1$

Out of our answer choices, we can pick D.

And we're done!

7 0

3 years ago

The difference of two numbers is 3. Their sum is - 24. Find the numbers.

Katarina [22]

Answer:

y = -13.5

x = -10.5

Step-by-step explanation:

Hi there!

Let the two numbers be equal to <em>x</em> and <em>y</em>.

The difference of two numbers is 3 ⇒ x - y = 3

Their sum is - 24 ⇒ x + y = -24

Solve using elimination:

x - y = 3

x + y = -24

Add the two equations:

x + x - y + y = 3 - 24

2x = -21

x = -10.5

Solve for y:

-10.5 - y = 3

- y = 3 + 10.5

y = -13.5

I hope this helps!

4 0

3 years ago