Find the sum of the finite geometric sequence

Mathematics

1 answer:

lions [1.4K]4 years ago

6 0

Answer:

Step-by-step explanation:

Use the geometric sum formula for in infinite sum. 20 terms of this basic formula is close enough The 20th term is 8.6 * 10^-10 which means this goes out to a number with 9 zeros after the decimal and before the 8.

Put another way, the tenth number of this series is the only one affected.

When you use a spreadsheet, it seems to know that the answer is 3/2 as the solution to the sum.

Solution.

Sum = a / (1 - r)

a = 1

r = 1/3

Sum = 1 / (1 - 1/3)

Sum = 1 // 2/3

sum = 3/2

Now you can worry about the 30.

30 * sum(1/3)^n = 30* 3/2 = 45

If there is something you want more information on, leave a note.

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3 years ago

A card is drawn at random from a deck of 52 playing cards. Find the probability that the card drawn is:

melomori [17]

probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

<u>Step-by-step explanation:</u>

Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:

an ace or a king

A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{8}{52}$

⇒ $probability = 0.1538$

a king or a diamond

A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{(13+4=17)}{52}$