An isosceles trapezoid with bases 12 and 16 is inscribed in a circle of radius 10. The center of the circle lies in the interior
1 answer:
The exact area of the isosceles trapezoid inscribed in a circle is determined as 196 sq units.
<h3>Height of the trapezoid</h3>The height of the trapezoid is calculated as follows;
From the image, the sum of h1 and h2 is the height of the trapezoid.
Each of the height will be calculated using Pythagoras theorem as follows;
- half of b1 = 12/2 = 6
- half of b2 = 16/2 = 8
h1² = r² - (b1/2)²
h1² = 10² - 6²
h1² = 64
h1 = √64
h1 = 8
h2² = r² - (b1/2)²
h2² = 10² - 8²
h2² = 36
h2 = √36
h2 = 6
Total height = 8 + 6 = 14
<h3>Area of the trapezoid</h3>A = ¹/₂(b₁ + b₂)H
A = ¹/₂(12 + 16) x 14
A = 196 sq units.
Learn more about area of trapezoid here: brainly.com/question/1463152
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