ANSWER:
the answer 130
Step-by-step explanation:
Answer:
a) The continuous rate of growth of this bacterium population is 45%
b) Initial population of culture at t = 0 is 950 bacteria
c) number of bacterial culture contain at t = 5 is 9013 bacteria
Step-by-step explanation:
The number of bacteria in a culture is given by
n(t) = 950
a) rate of growth is
Bacteria growth model N(t) = no
Where r is the growth rate
hence r = 0.45
= 45%
b) Initial population of culture at t = 0
n(0) = 950
= 950
= 950 bacteria
c) number of bacterial culture contain at t = 5
n(5) = 950
= 950
= 9013.35
= 9013 bacteria
i think its twenty hours.....but dont take my word on it im not 100% on it
Answer:
D. No, because the sample size is large enough.
Step-by-step explanation:
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
If the sample size is higher than 30, on this case the answer would be:
D. No, because the sample size is large enough.
And the reason is given by The Central Limit Theorem since states if the individual distribution is normal then the sampling distribution for the sample mean is also normal.
From the central limit theorem we know that the distribution for the sample mean
is given by:
If the sample size it's not large enough n<30, on that case the distribution would be not normal.
9514 1404 393
Answer:
12 liters
Step-by-step explanation:
The kerosene usage is assumed to be jointly proportional to the number of stoves and the number of hours. That is ...
v = k·s·h . . . . . for s stoves running h hours
Then the value of k is ...
k = v/(sh) = (16 L)/(12·14) = 2/21 . . . . liters per stove-hour
Then the volume of kerosene required for 7 stoves and 18 hours is ...
v = (2/21)·s·h
v = (2/21)(7)(18) = 12 . . . liters