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Goryan [66]
2 years ago
11

Suppose that the function f is defined, for all real numbers, as follows.

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
6 0

The solutions of the function are:

  • When f(x) = -4, the solution is -4
  • When f(x) = -2, the solution is -5/2
  • When f(x) = 0, the solution is -1

<h3>How to solve for the equation </h3>

The equation is given as

\frac{3}{4} x-1\\\\

When x = -4

3/4 * -4 -1

= -12/4 - 1

= -4

When x = -2

3/4*(-4) - 1

= -6/4 - 1/1

Take the lcm

-10/4

= -5/2

When x = 0

3/4(0) - 1

= -1

When f(x) = -4, the solution is -4

When f(x) = -2, the solution is -5/2

When f(x) = 0, the solution is -1

Read more on real numbers here:

brainly.com/question/155227

#SPJ1

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Katyanochek1 [597]

Answer:

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Step-by-step explanation:

In the negatives, If you take away the negative the lower number is more.

Think about a number line, if you are at -1/5, it means that you are 1/5 away from 0. If you are at -10/4, It means that you are 10,4 away from 0.

In conclusion, -1/5>-10/4

pls mark Brainliest

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Hello,

answer B

2

Step-by-step explanation:

\dfrac{2}{x} -\dfrac{x}{x+5} =\dfrac{10}{x^2+5x} \\\\we\ suppose\ x\neq 0\ and\ x\neq -5\\\\\text{Reducing to the same denominator}\\\dfrac{2(x+5)-x^2}{x(x+5)} =\dfrac{10}{x^2+5x} \\\\Simplify\ by\ x^2+5x\\\\2x+10-x^2=10\\\\-x^2+2x=0\\\\-x(x-2)=0\\\\roots\ are\ 2 \ and\ 0\ (to\ be\ excluded)\\\\Root=2\\

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