Answer:
I. L = 10.35 feet
II. W = 93.15 feet.
Step-by-step explanation:
Let the length of the rectangle be L.
Let the width of the rectangle be W.
Given the following data;
Perimeter of rectangular field = 1700 feet
Translating the word problem into an algebraic expression, we have;
W = 9L
Mathematically, the formula for the perimeter of a rectangle is;
P = 2(L + W)
A. To write an equation;
X = P = 2(L + W)
B. To find the dimensions of the field;
207 = 2(L + 9L)
207 = 2L + 18L
207 = 20L
L = 207/20
L = 10.35 feet
To find the weight;
W = 9L
W = 9 * 10.35
W = 93.15 feet.
Therefore, the width of the field is
93.15 feet and the length of the field is
10.35 feet.
Answer:
tan B = 12/5
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp side/ adj side
tan B = 12/5
Material=wall+2*side and material is 40 ft so:
40=w+2s
w=40-2s
Area=ws, using w from above we get:
A=(40-2s)s
A=40s-2s^2
dA/ds=40-4s and d2A/ds2=-4
Since d2A/ds2 is a constant negative acceleration, when dA/ds=0, A(s) is at an absolute maximum.
dA/ds=0 when 4s=40, s=10 ft
And since w=40-2s, w=20 ft
So the dimensions of the pen are 20 ft by 10 ft, with the 20 ft side being opposite the wall. And the maximum possible area is thus 200 ft^2
Answer:
Step-by-step explanation:
In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:
a = -32 ft/s/s
v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)
Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)
t = ?? sec.
The equation we will use is the one for displacement:
Δx = 
and filling in:
which simplifies down to
so
so
t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)
Now we use that time in the x-dimension. Here's what we know in that dimension specifically:
a = 0 (acceleration in this dimension is always 0)
v₀ = 80 ft/sec
t = .968 sec
Δx = ?? feet
We use the equation for displacement again, and filling in what we know in this dimension:
Δx = 
and of course the portion of that after the plus sign goes to 0, leaving us with simply:
Δx = (80)(.968)
Δx = 77.46 feet
Using the tangent rule:
Tangent(angle) = Opposite leg / Adjacent leg
We will use the 23 degree angle to solve for x.
Tangent(23) = X / 6
x = 6 * tangent(23)
x = 2.5
