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1 year ago

What is the slope of a line perpendicular to the line whose equation is 2x+3y=21. Fully simplify your answer.

1 answer:

3 0

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$2x+3y=21\implies 3y=-2x+21\implies y=\cfrac{-2x+21}{3} \\\\\\ y=\cfrac{-2x}{3}+\cfrac{21}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+7\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

therefore then

$\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-2}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-2}\implies \cfrac{3}{2}}}$

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Determine whether the sequence converges or diverges. If it converges, give the limit.

vaieri [72.5K]

Answer:

The given series converges and $\lim_{n \to \infty} a_n =0$

Step-by-step explanation:

Given is 108, -18, 3,...

It is an alternate series. An alternate series is convergent if:

1. The series is decreasing.

2. If the last term (n-th term) of series converges to 0.

<u>Since each next term is less than its preceding term, so it is decreasing.</u>

First term, a = 108

Second term = -18

Common ratio, r = -18/108 = -1/6

General term, aₙ = a*rⁿ = 108*(-1/6)ⁿ

<u>When n increases to infinity, the exponent term will decreases to zero, and last term (n-th term) will converge to 0 as well.</u>

Hence, the given series converges.

Now limit will be: $\lim_{n \to \infty} a_n$

$\lim_{n \to \infty} 108*(-1/6)^n \\= 108*(-1/6)^\infty \\= 108*(1/\infty) \\= 108*0 \\= 0$

Hence, $\lim_{n \to \infty} a_n =0$

7 0

2 years ago

Suppose that only 65% of all drivers in a certain state wear a seat belt. a random sample of 80 drivers is selected. what is the

jonny [76]

Answer:

Pr(X >42) = Pr( Z > -2.344)

= Pr( Z< 2.344) = 0.9905

Step-by-step explanation:

The scenario presented can be modeled by a binomial model;

The probability of success is, p = 0.65

There are n = 80 independent trials

Let X denote the number of drivers that wear a seat belt, then we are to find the probability that X is greater than 42;

Pr(X > 42)

In this case we can use the normal approximation to the binomial model;

mu = n*p = 80(0.65) = 52

sigma^2 = n*p*(1-p) = 18.2

Pr(X >42) = Pr( Z > -2.344)

= Pr( Z< 2.344) = 0.9905

7 0

2 years ago

Someone lmk what the answer is

Elodia [21]

$f(-7) = -(-7)^2 - 10 \cdot (-7) + 16\\= -49 + 70 + 16\\= 22$

7 0

3 years ago

42 is 21% of what number

Gnom [1K]

$\begin{array}{ccc}42&-&21\%\\x&-&100\%\end{array}\ \ \ \ \ |cross\ multiply\\\\21x=42\times100\\\\21x=4200\ \ \ \ \ |divide\ both\ sides\ by\ 21\\\\\boxed{x=200}\leftarrow answer$

5 0

2 years ago

Read 2 more answers

Please help !!!!!!!!!

Dmitrij [34]

Answer:

9^2= 81, √25= 5, 21^2= 441, √4= 2, √144= 12, 16^2= 256, √625= 25, (-11)^2=121

3 0

2 years ago