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Readme [11.4K]
2 years ago
11

Algebra 2 please help ASAP

Mathematics
2 answers:
katrin2010 [14]2 years ago
6 0
C . Is the correct answer
Katarina [22]2 years ago
4 0

Answer:

C. there is no solution

Step-by-step explanation:

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If x varies inversely as the square of y and if x=3 when y=-1, what is the value of x when y =3
lyudmila [28]

Answer:

x would be (1/3) when y = 3.

Step-by-step explanation:

The question states that x varies "inversely" as y^2. In other words, there is a non-zero number a (a constant) such that:

\displaystyle x = \frac{a}{y^2}.

The challenging part is to find the value of a in this equation.

Given that x = 3 when y = -1, replace the x in this equation with 3 and y with (-1). This equation should still be valid:

\displaystyle 3 = \frac{a}{(-1)^{2}}.

Solve for a:

a = 3 \times (-1)^2 = 3.

Hence, the relation between x and y becomes:

\displaystyle x = \frac{3}{y^2}.

Find the value of x when y = 3 by replacing the y in this equation with 3.

\displaystyle x = \frac{3}{3^2} = \frac{1}{3}.

In other words, the value of x would be \displaystyle \frac{1}{3} when y = 3.

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3 years ago
I really need some help it's hard to understand!
Vedmedyk [2.9K]
C you just add them divide by 2
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4 years ago
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Step-by-step explanation:

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