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1 year ago

Find the tangent of angle Θ in the triangle below.

Mathematics

1 answer:

Rina8888 [55]1 year ago

4 0

Answer: $\frac{\sqrt{65}}{4}$

Step-by-step explanation:

By the Pythagorean theorem, the unknown side has length

$\sqrt{9^{2}-4^{2}}=\sqrt{65}$

Therefore,

$\tan \theta=\boxed{\frac{\sqrt{65}}{4}}$

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Calculate the area of triangle ABC with altitude CD, given A(6,-2) B(1,3) C(5,5) D(2,2)

Vikki [24]

The area will be half the product of the lengths of AB and CD.

|AB| = √((6-1)² +(-2-3)²) = 5√2
|CD| = √((5-2)² +(5-2)²) = 3√2

Area = (1/2)*(5√2)*(3√2) = (1/2)*(15*2) = 15

The appropriate choice is ...
D: 15 square units

6 0

2 years ago

Kyle was playing a new video game.He scored 128 points on his first game.He scored 305 points on his second game,and 490 on his

Ivahew [28]

First game= 128
Second game= 305
Third game= 490

Add the points per game together.

= 128 + 305 + 490
= 923 points

ANSWER: He scored 923 points during the three games.

Hope this helps! :)

5 0

2 years ago

Question 15 (1 point)

insens350 [35]

The inver of given function will be (1,-3).

7 0

3 years ago

Graph a triangle on the coordinate plane. Choose 1 transformation (reflection, rotation,

BlackZzzverrR [31]

Answer:

The answer in the procedure

Step-by-step explanation:

we have the right triangle ABC

The pre-image coordinates are

$A(0,0),B(0,3),C(4,0)$

The transformation to use is the translation

The rule of the translation is

$(x,y)-----> (x+10,y)$

That means----> The translation is 10 units to the right

The image coordinates are

Applying the rule of the translation

$A'(0+10,0)=A'(10,0)$

$B'(0+10,3)=B'(10,3)$

$C'(4+10,0)=C'(14,0)$

using a graphing tool

see the attached figure

3 0

2 years ago

Brilliant_brown [7]

Simple.....

you have $\frac{18}{a} =7
$

to find what a is....simplify/multiply both sides....

$a* \frac{18}{a} =7*a$

simplifying it too....

18=7a

$\frac{18}{7} = \frac{7a}{7}$

$\frac{18}{7} =a$

Thus, your answer, C.

5 0

3 years ago