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1 year ago

Pick the 3 correct Python functions that parse and output only the date and time part of each log in log.txt as follows.

Computers and Technology

1 answer:

Mila [183]1 year ago

8 0

Answer:

1, 4, 5

Explanation:

parse2:

. In this case it's passing "r" as an argument, which really does absolutely nothing, because whenever you call open("file.txt") it defaults to reading mode, so all you're doing is explicitly passing the "r". So let's look at the first line. Whenever you call str.split() without any arguments, by default it splits it by empty text, and filters any empty text. So str.split() is not the same as str.split(" ") although it has similar behavior. " ".split(" ") will output ['', '', '', '', '', ''], while " ".split() will output []. So in this case the line.split() will split the string '10.1.2.1 - car [01/Mar/2022:13:05:05 +0900] "GET /python HTTP/1.0" 200 2222' into the list ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']. As you can see the the data is split into two pieces of text, AND they include the brackets in both strings. So when it gets the 3 index and strips it of the "[]" it will have the incomplete date

parse3:

In this instance the "r" does nothing as mentioned before the "r" is already defaulted whenever you call open("file.txt") so open("file.txt") is the same as open("file.txt", "r"). So in this case we won't be working left to right, we're going inside the brackets first, kind of like in math you don't don't work left to right in equation 3 + 3(2+3). You work in the brackets first (inside brackets you do left to right). So the first piece of code to run is the line.split("[" or "]"). I actually kind of misspoke here. Technically the "[" or "]" runs first because this doesn't do what you may think it does. The or will only return one value. this is not splitting the line by both "[" and "]". The, or will evaluate which is true from left to right, and if it is true, it returns that. Since strings are evaluated on their length to determine if they're true. the "[" will evaluate to true, because any string that is not empty is true, if a string is empty it's false. So the "[" will evaluate to true this the "[" or "]" will evaluate to "[". So after that the code will run line.split("[") which makes the list: ['10.1.2.1 - car ', '01/Mar/2022:13:05:05 +0900] "GET /python HTTP/1.0" 200 2222']. Now the [3:5] will splice the list so that it returns a list with the elements at index 3 (including 3) to 5 (excluding 5). This returns the list: [], because the previous list only has 2 elements. There are no elements at index 3 to 5 (excluding 5). So when you join the list by " ", you'll get an empty string

parse4:

So I'm actually a bit confused here, I thought the "r+" would open the file in read-writing mode, but maybe this is a different version of python I have no idea, so I'm going to assume it is reading/writing mode, which just means you can read and write to the file. Anyways when you split the line by doing line.split(), as mentioned before it will split by empty spaces and filter any empty spaces. This line will return: ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']. and then you splice the list from indexes 3 to 5 (excluding 5). This will return the list: ['[01/Mar/2022:13:05:05', '+0900]'] which has the two pieces of information you need for the date. Now it joins them by a space which will output: '[01/Mar/2022:13:05:05 +0900]'. Now when you strip the "[]" you get the string: '01/Mar/2022:13:05:05 +0900' which is the correct output!

parse 5:

So in this example it's using re.split. And the re.split is splitting by "[" or "]" which is what re.split can be used for, to split by multiple strings, which may be confused by string.split("[" or "]") which is not the same thing as explained above what the latter does. Also the reason there is a backslash in front of the [ and ] is to escape it, because normally those two characters would be used to define a set, but by using a \ in front of it, you're essentially telling regex to interpret it literally. So in splitting the string by "[" and "]" you'll get the list: ['10.1.2.1 - car ', '01/Mar/2022:13:05:05 +0900', ' "GET /python HTTP/1.0" 200 2222'] which has 3 elements, since it was split by the [ and the ]. The second element has the date, so all you need to do is index the list using the index 1, which is exactly what the code does

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Write a program that prints the block letter “B” in a 7x7 grid of stars like this:

makkiz [27]

Answer:

output = ""
for i in range(7):
if(i % 3 == 0):
for i in range(5):
output+= "*"
output += "\n"
else:
for i in range(2):
output += "* "
output += "\n"
print(output)

Explanation:

The solution code is written in Python 3.

Firstly, create a output variable that holds an empty string (Line 1).

Create an outer loop that will loop over 7 times to print seven rows of stars (Line 2). In row 0, 3 and 6 (which are divisible by 3) will accumulate up to 5 stars using an inner loop (Line 4-5) whereas the rest of the row will only print two stars with each start followed by a single space (Line 8-9) using another inner loop.

At last, print the output (Line 12).

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3 years ago

Functions of barriers include (mark all that apply): A. Define boundaries B. Design layout C. Deny access D. Delay access

gayaneshka [121]

Answer:

A. Define boundaries

C. Deny access

D. Delay access

Explanation:

A barrier is a material or structure used to prevent or block access. Barriers can either be natural or structural and are used for many purposes usually for security reasons. The following are functions of barriers either natural or structural:

Define areas of boundaries
Delay or slow access. Example is the use of speed bumps to slow down vehicles.
Provide access to entrances such as the use of gates
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3 years ago

You can be sentenced to up to 180 days in jail for driving with a license that was suspended for _________ .

Yanka [14]

Answer:c\

Explanation:

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3 years ago

Use the arr field and mystery () method below.

kolezko [41]

Answer:

The sum of all positive even values in arr

Explanation:

We have an array named arr holding int values

Inside the method mystery:

Two variables s1 and s2 are initialized as 0

A for loop is created iterating through the arr array. Inside the loop:

num is set to the ith position of the arr (num will hold the each value in arr)

Then, we have an if statement that checks if num is greater than 0 (if it is positive number) and if num mod 2 is equal to 0 (if it is an even number). If these conditions are satisfied, num will be added to the s1 (cumulative sum). If num is less than 0 (if it is a negative number), num will be added to the s2 (cumulative sum).

When the loop is done, the value of s1 and s2 is printed.

As you can see, s1 holds the sum of positive even values in the arr

7 0

3 years ago

(ANSWER!)

andreev551 [17]

Answer:

it doesn't? maybe it helps by resetting it but other than that I don't think It does anything

4 0

3 years ago

Read 2 more answers