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Setler79 [48]
2 years ago
12

Im trying to figure out the answer

Mathematics
1 answer:
Molodets [167]2 years ago
3 0

Step-by-step explanation:

\sqrt{35} =\sqrt{5} *\sqrt{7};

all the details are in the attachment.

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Simplify the cube root in simplest radical form.<br> 9x374<br> Please help
algol [13]

Answer:

D. xy\sqrt[3]{9y}

Step-by-step explanation:

\sqrt[3]{9x^3y^4}

\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}

The \sqrt[3]{x^3} cancels out to become x:

\sqrt[3]{9}x\sqrt[3]{y^4}

Split the y^4=y*y^3

\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}

\sqrt[3]{y^3} =y

xy\sqrt[3]{9} \sqrt[3]{y}

Put the cube root of y and cube root of 9 together:

xy\sqrt[3]{9y}

6 0
3 years ago
What is the domain of f(x) = 3^x -2?
user100 [1]

Answer:

"all real numbers"

Step-by-step explanation:

This is an exponential function.  The domain of the basic exponential function 3^x is "all real numbers."  This domain also applies to f(x) = 3^x - 2.

8 0
3 years ago
What between 250 and 300
Fiesta28 [93]

Answer:

5 and 0 between 250 and 300

5 0
3 years ago
Can someone plz help me with Algebra 2....... :) Will give Brainliest!!
Anarel [89]
Using logarithms property of log(x)+log(y)=log(xy)
so here, you can sum the equation to;
log((x+6)*(x-6))=2
so you can simply say that;
log_{8}((x+6)( x-6))=2
and by multiplying (x+6)*(x-6)
log_{8}(x^2-36)=2
and as you know also that;
a^{b}=c is same as log _{a}c=b
so you can simply state it as;
8^2=x^2-36&#10;64=x^2-36&#10;64+36=x^2&#10;x^2=100&#10;x=10
And you can check your work by substituting with 10 instead of x in the original function.
Hope this helps!
6 0
3 years ago
What is the cost per unit called
lord [1]
A unit cost<span> is the total expenditure incurred by a company to produce, store and sell one </span>unit<span> of a particular product or service. </span>Unit costs<span> include all fixed </span>costs<span>, or overhead </span>costs<span>, and all variable </span>costs<span>, or direct material </span>costs<span> and direct labor </span>costs<span>, involved in production.</span>
4 0
2 years ago
Read 2 more answers
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