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Anna [14]
2 years ago
10

I need help ASAP !?!?!?!?!!?!?!!??!

Mathematics
1 answer:
s2008m [1.1K]2 years ago
7 0

Answer:

First, do 15/12 then take that and divide by 500!

Step-by-step explanation:

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BARSIC [14]
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5 0
3 years ago
What is the derivative of 3x+5x
Vaselesa [24]

Answer:

\displaystyle \frac{d}{dx}[3x + 5x] = 8

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle y = 3x + 5x

<u>Step 2: Differentiate</u>

  1. Simplify:                                                                                                         \displaystyle y = 8x
  2. Derivative Property [Multiplied Constant]:                                                   \displaystyle y' = 8\frac{d}{dx}[x]
  3. Basic Power Rule:                                                                                         \displaystyle y' = 8

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
Ramiya is using the quadratic formula to solve a quadratic equation. Her equation is x =  after substituting the values of a, b
Scorpion4ik [409]

Answer:

0 = x2 + 3x + 2


7 0
3 years ago
Why the following triangles are congruent!
dimaraw [331]

Answer:

Because the sides BO and MA are marked with one line through the middle, which means those sides are congruent, angle A and Angle O are marked with one line, the angles are congruent, and angles W and N are marked with two lines, which means they are congruent. Therefore the triangles are congruent

7 0
3 years ago
A grain silo has the shape of a right circular cylinder surmounted by a hemisphere. If the silo is to have a volume of 505π ft3,
Romashka-Z-Leto [24]

Answer:

radius   x  = 3 ft

height   h = 23,8  ft

Step-by-step explanation:

From problem statement

V(t)  = V(cylinder) + V(hemisphere)

let x be radius of base of cylinder (at the same time radius of the hemisphere)

and h the height of the cylinder, then:

V(c)  = π*x²*h       area of cylinder = area of base + lateral area

                                              A(c)  = π*x²  +   2*π*x*h

V(h) = (2/3)*π*x³   area of hemisphere   A(h)  =   (2/3)*π*x²

A(t)  =  π*x²  +   2*π*x*h +   (2/3)*π*x²

Now A as fuction of x    

total volume   505  = π*x²*h  +  (2/3)*π*x³

h = [505 - (2/3)* π*x³ ]  /2* π*x    

Now we have the expression for A as function of x

A(x) =  3π*x² + 2π*x*h     A(x) = 3π*x² + 505  - (2/3)π*x³

Taking derivatives both sides

A´(x) =  6πx -  2πx²              A´(x) =  0         6x  - 2x²  = 0

x₁  =  0  we dismiss

6 - 2x = 0

x = 3     and   h = [505 - (2/3)* π*x³]/2* π*x

h  =  (505 - 18.84) / 6.28*3

h  = 23,8  ft

7 0
3 years ago
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