All categories

2 years ago

I need help ASAP !?!?!?!?!!?!?!!??!

Mathematics

1 answer:

s2008m [1.1K]2 years ago

7 0

Answer:

First, do 15/12 then take that and divide by 500!

Step-by-step explanation:

You might be interested in

????????? h e l p ????????

BARSIC [14]

C.

She said that I don’t need her 54

5 0

3 years ago

What is the derivative of 3x+5x

Vaselesa [24]

Answer:

$\displaystyle \frac{d}{dx}[3x + 5x] = 8$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = 3x + 5x$

Step 2: Differentiate

Simplify: $\displaystyle y = 8x$
Derivative Property [Multiplied Constant]: $\displaystyle y' = 8\frac{d}{dx}[x]$
Basic Power Rule: $\displaystyle y' = 8$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago

Ramiya is using the quadratic formula to solve a quadratic equation. Her equation is x = after substituting the values of a, b

Scorpion4ik [409]

Answer:

0 = x2 + 3x + 2

7 0

3 years ago

Why the following triangles are congruent!

dimaraw [331]

Answer:

Because the sides BO and MA are marked with one line through the middle, which means those sides are congruent, angle A and Angle O are marked with one line, the angles are congruent, and angles W and N are marked with two lines, which means they are congruent. Therefore the triangles are congruent

7 0

3 years ago

A grain silo has the shape of a right circular cylinder surmounted by a hemisphere. If the silo is to have a volume of 505π ft3,

Romashka-Z-Leto [24]

Answer:

radius x = 3 ft

height h = 23,8 ft

Step-by-step explanation:

From problem statement

V(t) = V(cylinder) + V(hemisphere)

let x be radius of base of cylinder (at the same time radius of the hemisphere)

and h the height of the cylinder, then:

V(c) = π*x²*h area of cylinder = area of base + lateral area

A(c) = π*x² + 2*π*x*h

V(h) = (2/3)*π*x³ area of hemisphere A(h) = (2/3)*π*x²

A(t) = π*x² + 2*π*x*h + (2/3)*π*x²

Now A as fuction of x

total volume 505 = π*x²*h + (2/3)*π*x³

h = [505 - (2/3)* π*x³ ] /2* π*x

Now we have the expression for A as function of x

A(x) = 3π*x² + 2π*x*h A(x) = 3π*x² + 505 - (2/3)π*x³

Taking derivatives both sides

A´(x) = 6πx - 2πx² A´(x) = 0 6x - 2x² = 0

x₁ = 0 we dismiss

6 - 2x = 0

x = 3 and h = [505 - (2/3)* π*x³]/2* π*x

h = (505 - 18.84) / 6.28*3

h = 23,8 ft

7 0

3 years ago