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1 year ago

What is the deposit of $40

Mathematics

1 answer:

Sliva [168]1 year ago

4 0

The integer form is + 40.

The integer form is - 25

<h3>What is an integer?</h3>

An integer is a whole number from the set of negative, non-negative, and positive numbers.

Therefore, integers can be written without fractional components.

Hence, integers may include negative or positive numbers . Examples are -1, 2, 5, -8, 9 and many more.

A deposit of 40 dollars means gain. Therefore, the integer form is + 40.

A loss of 25 pounds mean loss. Therefore, the integer form is - 25

learn more on integers here:brainly.com/question/15267155

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One peach weigh 5 ounces. bella buys 8 peaches. what is the total weight of the peach

Oliga [24]

Answer:

40 ounces

Step-by-step explanation:

well if every peach weighs 5 ounces and she buys 8, just do 8 x 5 and you get 40

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3 years ago

4. Dean Pelton wants to perform calculations to impress the accreditation consultants, but upon asking for information about GPA

Leya [2.2K]

Answer:

the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

Step-by-step explanation:

Let assume that n should represent the number of the students

SO, $\bar x$ can now be the sample mean of number of students in GPA's

To obtain n such that $P( \bar x \leq 2.3 ) \leq .04$

⇒ $P( \bar x \geq 2.3 ) \geq .96$

However ;

$E(x) = \int\limits^4_2 Dx (2+e^{-x} ) 4x = D \\ \\ = D(e^{-x} (e^xx^2 - x-1 ) ) ^D_2 = 12.314 D$

$E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D$

Similarly;

$D\int\limits^4_2(2+ e^{-x}) dx = 1$

⇒ $D*(2x-e^{-x} ) |^4_2 = 1$

⇒ $D*4.117 = 1$

⇒ $D= \dfrac{1}{4.117}$

$\mu = E(x) = 2.991013 ; \\ \\ E(x^2) = 9.28103$

∴ $Var (x) = E(x^2) - E^2(x) \\ \\ = .3348711$

Now; $P(\bar \geq 2.3) = P( \bar x - 2.991013 \geq 2.3 - 2.991013) \\ \\ = P( \omega \geq .691013) \ \ \ \ \ \ \ \ \ \ (x = E(\bar x ) - \mu)$

Using Chebysher one sided inequality ; we have:

$P(\omega \geq -.691013) \geq \dfrac{(.691013)^2}{Var ( \omega) +(.691013)^2}$

So; $(\omega = \bar x - \mu)$

⇒ $E(\omega ) = 0 \\ \\ Var (\omega ) = \dfrac{Var (x_i)}{n}$

∴ $P(\omega \geq .691013) \geq \dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2}$

To determine n; such that ;

$\dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2} \geq 0.96 \\ \\ \\ (.691013)^2(1-.96) \geq \dfrac{-3348711*.96}{n}$

⇒ $n \geq \dfrac{.3348711*.96}{.04*(.691013)^2}$

$n \geq 16.83125$

Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

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3 years ago

13. Use a net to find the surface area of the prism.

Viefleur [7K]

Answer:

516 inches

Step-by-step explanation:

2(8(6)) + 2(15(6)) + 2(15(8))

96 + 180 + 240 = 516in

The answer is 516in

*Please mark me the brainliest. Thanks

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3 years ago

304 students went on a field trip. seven buses were filled and 17 students traveled in cars. how many students were in each bus?

nlexa [21]

41 students
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304: total students
17: riding in car
7: number of buses
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304 - 17 = 287
287 divided by 7 = 41

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3 years ago

Which is the best definition of an exterior angle of a triangle

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Answer:

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Step-by-step explanation:

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3 years ago